Use an area model to solve. 1 3/4 X 2 1/2
1 answer:
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Answer:
Length of a side of a square = 2√2 units
Step-by-step explanation:
Let the length of a square is 'x' units.
Therefore, Area of the square A = (Side)²
= x² square units
And by Pythagoras theorem,
(Diagonal)²= (Side 1)² + (Side 2)²
= x² + x²
= 2x²
Diagonal 'p' = x√2 units
It is given in the question that area of the square is increasing four times as fast as the diagonals.
-------(1)
Similarly,
Now by placing the value of and
in equation (1),
Since,
x = 2√2
Therefore, length of a side of the square is 2√2.
Answer:
(x-1)²/49 + (y+3)²/16.51 = 1
Step-by-step explanation:
vertex (8,-3) Foci (6.7,-3) center (h,k) = (1,-3) , major axis parallel to x axis
a is the distance of the vertex from the center, and c is the distance of the foci from the center. b is semi-minor axis
b² = a² - c² Ellipse equation: (x-h)²/a² + (y-k)²/b² = 1
a = 8-1 = 7 c = 6.7 - 1 = 5.7
b² = 7² - 5.7² = 16.51
Ellipse equation: (x-1)²/49 + (y- -3)²/16.51 = 1 i.e. (x-1)²/49 + (y+3)²/16.51 = 1
