Step-by-step explanation:
If we use this formula then
X is 54 y is 45
54 + 45 = 11(54 + 45)
99 = 11(99)
99 = 1089
= 1089 - 99
= 990
<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
Answer:
-4/2
Step-by-step explanation:
just take 4 and divide it by -2 and youll get the common ratio as-2
Hope it helps
Answer:
r = 12
Step-by-step explanation:
DG + GM = DM , substitute values
r + 3 + 4r - 28 = 35 , that is
5r - 25 = 35 ( add 25 to both sides )
5r = 60 ( divide both sides by 5 )
r = 12
