this is the answer to this question - Two weather tracking stations are on the equator 146 miles apart. A weather balloon is located on a bearing of N 35°E from the western station and on a bearing of N 23°E from the eastern station. How far is the balloon from the western station?
Answer:
Reasons:
The given parameters are;
Distance between the two stations = 146 miles
Location of the weather balloon from the Western station = N35°E
Location of the weather balloon from the Eastern station = N23°E
The location of the station = On the equator
Required:
The distance of the balloon from the Western station
Solution:
- The angle formed between the horizontal, and the line from the Western station
to the balloon = 90° - 35° = 55°
- The angle formed between the horizontal, and the line from the Eastern station
to the balloon = 90° + 23° = 113°
The angle at the vertex of the triangle formed by the balloon and the two stations is 180° - (55 + 113)° = 12°
By sine rule,
Distance from balloon to western station = 146/sin(12 dg) = Distance from balloon to western station/sin(113 dg)
Therefore;
Distance from balloon to western station = 146/sin(12 dg) x sin(113 dg) ~ 646.4
Step-by-step explanation:
Area of a triangle:
A= (1/2)(bh)
In this problem we are given:
A= 178.5
b= h+4 in
h= UNKNOWN ("h")
Plug in our values into the area equation and solve for "h":
(multiply each side by 2 to get rid of the 1/2)
(357/21=17)
(solve both inequalities separately)
( a negative height is not possible so, this answer is incorrect.)
Answer: base = (h+4)= (17+ 4)
b= 21 in h= 17inPlease comment with any further questions! :)
Answer:
10000
Step-by-step explanation:
Well substitute it
(5*2)^4
now follow order of operations (Parenthesis, exponents, multipication-division left to right, etc.)
5*2=10
10^4=10000
so the answer would be
10000 if y is 2
Answer:
Step-by-step explanation:
The supplement of 102 = 180 - 102 = 78
It is the interior angle of the given exterior angle.
It is also the enclosed angle of the isosceles triangle
Each of the other two angles = y
180 = 2*y + 78 Subtract 78 from both sides
180 - 78 = 2y Combine
102 = 2y Divide by 2
102 / 2 = y
51 = y
The smaller triangle on your right has 2 equal sides that are marked.
The angle you just found = <2 and the vertically opposite angle of the 51
So <2 = 51
