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konstantin123 [22]
3 years ago
6

The price of a certain new car increases by the same amount each year. The first year it was ​$24,000 and in the 5th year it was

​$28,000. In which year will the car cost $30,000?
Mathematics
1 answer:
Leona [35]3 years ago
7 0
It increased in price by $4,000 in 4 years . That is by $1000 per year.

So in year 7 it will cost  28,000 + 2,000 = $30,000

Answer  7th year.
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C. Gage bought a new car for $29,000 to use while he is away at college. The car depreciates (decreases in value) by 11% annuall
OverLord2011 [107]

Answer:

a. The value of the car will be $18,195.25

b. (i) 2.5 hours

(ii) 25 problems each

Step-by-step explanation:

a. To calculate the value of the car after four years, what we shall use is the exponential formula below;

F = PV( 1 - r)^t

where F is the value at year 4

PV is the present price = $29,000

r is the rate = 11% = 11/100 = 0.11

t is the time = 4 years

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The value of the car when he graduates will be $18,195

b. Let the number of hours it will take for both to have written the same number if problems

be x

For Ms B, the number of problems she would have written at that time will be 10 + 6(x)

For Ms D , the number of problems will be 10 * x = 10x

To get the time it will take for both to write same number of problems, we will need to equate the number of problems they would have written by hour x

Hence;

10 + 6x = 10x

10x-6x = 10

4x = 10

x = 10/4 = 2.5 hours

The number of problems would be;

For Ms B = 6(2.5) + 10 = 15 + 10 = 25

For Ms D = 10(2.5) = 25

They both would have written 25 problems at that time

3 0
3 years ago
Homework, pls help ( 10 points )
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avanturin [10]

Answer:

A= (3,1) ; B=(-2,-1) ; C=(-4,1) ; D=(-4,0)

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