<h3>Given</h3>
tan(x)²·sin(x) = tan(x)²
<h3>Find</h3>
x on the interval [0, 2π)
<h3>Solution</h3>
Subtract the right side and factor. Then make use of the zero-product rule.
... tan(x)²·sin(x) -tan(x)² = 0
... tan(x)²·(sin(x) -1) = 0
This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:
... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)
Then our equation becomes
... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0
... -sin(x)²/(1 +sin(x)) = 0
Now, we know the only solutions are found where sin(x) = 0, at ...
... x ∈ {0, π}
Answer:
3/5
Step-by-step explanation:
72/2 =36
120/2 =60
=36/60
36/2 = 18
60/2 = 30
=18/30
18/2=9
30/2 =15
= 9/15
9/3=3
15/3 =5
= 3/5
Answer:
281.25 miles
Step-by-step explanation:
2=250
1=125
0.5=62.5
0.25=31.25
250+31.25=281.25
Answer:
x = 62
Step-by-step explanation:
x and 118 form a linear pair (added up, they both equal 180 degrees)
So, 180-118 = 62 which is the measurement of x