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4vir4ik [10]
3 years ago
8

What is the simpler form of (2k²− k+ 3) + (5k²+ 3k +7)?

Mathematics
1 answer:
Kryger [21]3 years ago
6 0

Answer: 7k^2+2k+10

Step-by-step explanation: To simplify this, you need to combine like terms, which are just the numbers that have the same variables and exponents. Combine 2k^2 and 5k^5 and it is 7k^2 (Just add the coefficient). Then do 3k -k, which is 2k. k just represents 1, so basically, 3-1. Finally, 7 + 3, which is 10. Then, combine the results to form an expression, which is 7k^2+2k+10.

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1 gallon = 0.125 pints

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The value of y varies directly with x. If x = 3, then y = 22. What is the value of x when y equals 105
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Varies directly uses the formula: y/x = k

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Find the distance between the following points using the Pythagorean theorem: (-5, 4) and (8, -3)
3241004551 [841]

First, draw a diagram to visualize the situation:

As we can see, the difference between the x-coordinates of the points is the length of one leg of a right triangle, and the difference between the y-coordinates is the length of the other leg.

Then, for the given points (-5,4) and (8,-3), the distance given by the Pythagorean Theorem is:

\begin{gathered} d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\  \\ =\sqrt{(8--5)^2+(-3-4)^2} \\  \\ =\sqrt{(13)^2+(-7)^2} \\  \\ =\sqrt{169+49} \\  \\ =\sqrt{218} \\  \\ \approx14.7648... \end{gathered}

Therefore, the distance between the points (-5,4) and (8,-3) is: √218.

5 0
1 year ago
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