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3 years ago

What is the simpler form of (2k²− k+ 3) + (5k²+ 3k +7)?

Mathematics

1 answer:

Kryger [21]3 years ago

6 0

Answer: 7k^2+2k+10

Step-by-step explanation: To simplify this, you need to combine like terms, which are just the numbers that have the same variables and exponents. Combine 2k^2 and 5k^5 and it is 7k^2 (Just add the coefficient). Then do 3k -k, which is 2k. k just represents 1, so basically, 3-1. Finally, 7 + 3, which is 10. Then, combine the results to form an expression, which is 7k^2+2k+10.

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J= -2(3-k) make k the subject

lapo4ka [179]

Answer:

K=J+6/2

Step-by-step explanation:

J= -2(3-k)

simplify whats in the bracket

J= -6+2k

J+6=2k

Divide both sides by 2

J+6/2=2k/2

2 and 2 will cancel out

remaining K

So, Therefore K=J+6/2

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3 years ago

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ohaa [14]

Answer:

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Step-by-step explanation:

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prisoha [69]

Split up the interval [0, 2] into 4 subintervals, so that

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Each subinterval has width $\dfrac{2-0}4=\dfrac12$ . The area of the trapezoid constructed on each subinterval is $\dfrac{f(x_i)+f(x_{i+1})}4$ , i.e. the average of the values of $x^2$ at both endpoints of the subinterval times 1/2 over each subinterval $[x_i,x_{i+1}]$ .

So,

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nydimaria [60]

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3 years ago

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