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Evgesh-ka [11]
4 years ago
14

Which double-angle or half-angle identity would you use to verify that 1+cos2a=2/1+tan2a?

Mathematics
2 answers:
juin [17]4 years ago
8 0

In this case or scenario, the double-angle identity that should be used is the one for cosine. <span>

In totality, we shall need the following three trigonometric identities to end up with the equality: 

<span>1. cos (2a) = cos² (a) - sin² (a)
2. sin² (a) + cos² (a) = 1 
<span>3.  tan² (a) + 1 = sec² (a)

<span>Using identities 1 and 2 on the left-hand side of the equation, we get the following:</span>

1 + cos (2a) = 1 + cos² (a) - sin² (a) = 2 cos² (a) </span></span></span>

<span>

<span>Recalling that cos² (a) = 1 / sec² (a) and applying identity 3, we find the following:</span>

2 cos² (a) = 2 / sec² (a) = 2 / (1 + tan² (a)) </span>

 

Therefore giving us:

<span>2 cos² (a) = 2 / (1 + tan² (a))</span>

lesantik [10]4 years ago
6 0

Answer:

Its C. cos2a=cos^2a-sin^2a on  ed

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7 0
3 years ago
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Which of these is a complex number? <br><br> A. <br><br> B. <br><br> C. <br><br> D.
Step2247 [10]

Answer:

option D

\frac{8}{3} + \sqrt{\frac{-7}{3} }

Step-by-step explanation:

Given in the question are 4 number

5√1/3 - \frac{9}{\sqrt{7} }

2 - \frac{1}{\sqrt{11} }

9 + 3\sqrt{\frac{5}{2} }

\frac{8}{3} + \sqrt{\frac{-7}{3} }

A Complex Number is a combination of a Real Number and an Imaginary Number

<h3>Example </h3>

a + ib

where a is real number

            b is imaginary number

            i is 'lota' which is √-1

<h3>So according to the definition above </h3>

\frac{8}{3} + \sqrt{\frac{-7}{3} } is complex number in which

\frac{8}{3} is real part

\sqrt{\frac{7}{3} } \sqrt{-1} = \sqrt{\frac{7}{3} } i is the imaginary part

7 0
4 years ago
Simplify the expression: 7b^4c^3+6b^3c^4-3b^3c^4
SOVA2 [1]

Answer: 7b^(4)c^(3)+3b^(3)c^(4)

Step-by-step explanation: hope this helps have a nice day :)

7 0
2 years ago
What is the slope of the line going through A and B?
Pepsi [2]

The formula for slope is:  m  =  (y2 - y1) / (x2 - x1)   --->   m  =  (b - b) / (-a - a)  =  0/(-2a)  =  0

3 0
3 years ago
A simple random sample of 144 observations was taken from a large population. The sample mean and the standard deviation were de
Vera_Pavlovna [14]

Answer:

The standard error of mean = 10

Step-by-step explanation:

Given a simple sample of 144 observations was taken from a large population.

The size of large sample 'n' = 144

Given sample mean and the standard deviation were determined to be 1234 and 120 respectively.

Given standard deviation of sample (S)  = 120

The standard error of mean is determined by

                                                SE (X^{-} ) = \frac{S.D}{\sqrt{n} }

                                              SE (X^{-} ) = \frac{120}{\sqrt{144} } = 10

<u>Final answer</u>:-

The standard error of mean = 10

4 0
3 years ago
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