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Evgesh-ka [11]
4 years ago
14

Which double-angle or half-angle identity would you use to verify that 1+cos2a=2/1+tan2a?

Mathematics
2 answers:
juin [17]4 years ago
8 0

In this case or scenario, the double-angle identity that should be used is the one for cosine. <span>

In totality, we shall need the following three trigonometric identities to end up with the equality: 

<span>1. cos (2a) = cos² (a) - sin² (a)
2. sin² (a) + cos² (a) = 1 
<span>3.  tan² (a) + 1 = sec² (a)

<span>Using identities 1 and 2 on the left-hand side of the equation, we get the following:</span>

1 + cos (2a) = 1 + cos² (a) - sin² (a) = 2 cos² (a) </span></span></span>

<span>

<span>Recalling that cos² (a) = 1 / sec² (a) and applying identity 3, we find the following:</span>

2 cos² (a) = 2 / sec² (a) = 2 / (1 + tan² (a)) </span>

 

Therefore giving us:

<span>2 cos² (a) = 2 / (1 + tan² (a))</span>

lesantik [10]4 years ago
6 0

Answer:

Its C. cos2a=cos^2a-sin^2a on  ed

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Travka [436]
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100/40=2.5 or 250%

250% in production rate should be your answer.
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A fleet of nine taxis is to be dispatched to three airports in such a way that three go to airport a, five go to airport b, and
krok68 [10]

A fleet of nine taxis is to be dispatched to three airports in such a way that three go to airport A, five go to airport B, and one goes to airport C. In how many distinct ways can this be accomplished?

2.44) Refer to Exercise 2.43. Assume that taxis are allocated to airports at random.

a) If exactly one of the taxis is in need of repair, what is the probability that it is dispatched to airport C?

b) If exactly three of the taxis are in need of repair, what is the probability that every airport receives one of the taxis requiring repairs?

So, my answer to 2.44a is 1/9. Hopefully this is correct at least :)

For 2.44b, my guess was

(3C1)(1/3)(2/3)2 * (5C1)(1/3)(2/3)4 * 1/3

The solutions manual on chegg (which seems to be riddled with errors) says something completely different. Is my calculation correct?

8 0
3 years ago
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Please answer the question from the attachment.
spin [16.1K]

Hi,

7x²-2x-8=0, so a = 7, b= - 2, and c = -8.

You just need to apply the formula for square equations:

x_{1,2}=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-2)\pm\sqrt{(-2)^2-4\cdot 7\cdot (-8)}}{2\cdot 7}=\dfrac{2\pm\sqrt{228}}{14}=\dfrac{2\pm\sqrt{4\cdot 57}}{14}=\\\\=\dfrac{1\pm\sqrt{57}}7\Rightarrow x_1=\dfrac{1-\sqrt{57}}7,\;and\;x_2=\dfrac{1+\sqrt{57}}7.

Green eyes.

7 0
3 years ago
5v + 7f =28.70 if f is 2.85
adell [148]
Hey!

First, let's write the problem.
5v+7\left(2.85\right)=28.7
Multiply 7 with 2.85.
5v+19.95=28.7
Subtract 19.95 from both sides.
5v+19.95-19.95=28.7-19.95
5v=8.75
Divide both sides by 5.
\frac{5v}{5}=\frac{8.75}{5}
v=1.75

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish
3 0
3 years ago
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Plz help me!!!<br> im bouta put pic give meh second
adell [148]
<span>(a) What is the capacity of the container?
Volume = length * width * height
V = 4ft * 2ft * 3ft
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(b) How much material was used to make the container?Surface area = sum of 6 faces of the prism4 ft x 3 ft = 12 ft² → 12 ft² x 2 = 24 ft²4 ft x 2 ft = 8 ft² → 8 ft² x 2 = 16 ft²2 ft x 3 ft = 6 ft² → 6 ft² x 2 = 12 ft²
Surface area = 24 ft² + 16 ft² + 12 ft² = 52 ft²
6 0
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