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denpristay [2]
3 years ago
15

Select all the equations that have 9 as a solution.

Mathematics
2 answers:
bixtya [17]3 years ago
8 0

Answer:

2, 3 and 4 all solve to equal 9

Radda [10]3 years ago
7 0

Answer:

m x 3 = 27

p - 5 = 4

b + 4 = 13

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At the grocery store, Tina counts eight cartons with 6 eggs each, forty cartons with 12 eggs each, and twenty cartons with 18 eg
Darya [45]

A 100%. 8 cartons w/ 6 = 8 x 6, etc.

same w/ 40 x 12, ya know. hope i helped

5 0
4 years ago
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An 18-foot ladder leaned up against a wall forms an angle of 70 degrees with the ground. How high up the wall will the ladder re
Paladinen [302]

the ladder is 13.8 ft up the wall

6 0
4 years ago
Find all real solutions to the equation (x² − 6x +3)(2x² − 4x − 7) = 0.
Jet001 [13]

Answer:

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ;  x = \frac{2-(3)\sqrt{2}}{2}

Step-by-step explanation:

Relation given in the question:

(x² − 6x +3)(2x² − 4x − 7) = 0

Now,

for the above relation to be true the  following condition must be followed:

Either  (x² − 6x +3) = 0 ............(1)

or

(2x² − 4x − 7) = 0 ..........(2)

now considering the equation (1)

(x² − 6x +3) = 0

the roots can be found out as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

for the equation ax² + bx + c = 0

thus,

the roots are

x = \frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times(3)}}{2\times(1)}

or

x = \frac{6\pm\sqrt{36-12}}{2}

or

x = \frac{6+\sqrt{24}}{2} and, x = x = \frac{6-\sqrt{24}}{2}

or

x = \frac{6+2\sqrt{6}}{2} and, x = x = \frac{6-2\sqrt{6}}{2}

or

x = 3 + √6 and x = 3 - √6

similarly for (2x² − 4x − 7) = 0.

we have

the roots are

x = \frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-7)}}{2\times(2)}

or

x = \frac{4\pm\sqrt{16+56}}{4}

or

x = \frac{4+\sqrt{72}}{4} and, x = x = \frac{4-\sqrt{72}}{4}

or

x = \frac{4+\sqrt{2^2\times3^2\times2}}{2} and, x = x = \frac{4-\sqrt{2^2\times3^2\times2}}{4}

or

x = \frac{4+(2\times3)\sqrt{2}}{2} and, x = x = \frac{4-(2\times3)\sqrt{2}}{4}

or

x = \frac{2+3\sqrt{2}}{2} and, x = \frac{2-(3)\sqrt{2}}{2}

Hence, the possible roots are

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ; x = \frac{2-(3)\sqrt{2}}{2}

7 0
3 years ago
Write answer as an inequality solved for c ​
g100num [7]
He will spend at least $27. He has already spent $16

27-16=11

So, Henry will spend at least 11 more dollars

C ≥ 11
5 0
3 years ago
..................................................................................​
elena-14-01-66 [18.8K]

Answer:

Leonard please reply.....

5 0
3 years ago
Read 2 more answers
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