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3 years ago

Divide using Long division (6x^3-26x-21+x^2) by (-7+3x)

Mathematics

2 answers:

Dimas [21]3 years ago

6 0

Step-by-step explanation:

Hope it helps you in your learning process.

Rasek [7]3 years ago

3 0

The answer is 2x^2+5x+3

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6. Solve by factoring: 2x²-11x+14=0

Mariana [72]

Step-by-step explanation:

Solve 2x^2-11x+14=0 give me 2 ways to get the 2 values of x?

The first way is to make factors by middle-term splitting. You get (x-2)(2x-7)=0, so the solution is x=2,7/2.

The other way is to use the formula for the solution of roots. Roots= (-b+ rootD)/2a, (-b-rootD)/2a, if the equation is of the form ax^2+bx+c=0. Here D is the discriminant. D=b^2-4ac

How do I solve 12x^2+11x+2=0?

Solve for x. 5x3−2x2−47x−14=0?

How can I prove that x^2+2x+2=0?

Is the sequence X^2 + 2x -2 =0?

What are the steps to solve 2^(2x)-3(2^x) +2=0?

Lets assume your equation is of the form ax^2+ bx + c =0

First method :

By breaking 'b' factor of x into two parts using factors of 'ac' ( a *c)

like 2* 14 = 28 = 7* 4 ( b is 11 which could be splitted in values 7 and 4)

equation becomes 2x^2 -4x-7x+14 = 0

take out common factors 2x(x-2) -7 (x-2) = 0

which is (2x-7) (x-2) =0 ; x =2,7/2 are two values

Second method:

make equation in the form of (x+h)^ 2 - k = 0 ; then x+h = +sqrt(k) and -sqrt(k)

which will give x as -h+sqrt(k) , +sqrt(k)

2x^2 - 11x +14 =0 wil become x^2 -11/2 x + 7 = 0

which is (x-11/4)^2 + 7- 121/16 =0

(x-11/4)^2 = (121/16) - 7 = 9/16

x- 11/4 = 3/4 and -3/4

x = 14/4 and 8/4 = 7/2 and 2

3 0

2 years ago

Read 2 more answers

Find the final price CD player:89.95 discount: 15% tax:6%

vodka [1.7K]

76.53 * 1.06 = 81.12 = final cost of the cd player

7 0

3 years ago

Help me find the area of each hexagon and explain to me how

wolverine [178]

Answer:

sorry I only know how to solve perimeter

4 0

3 years ago

A 7/16 inch bolt is used in a machine . what is the length of the bolt writtin as a decimal?

Ierofanga [76]

In decimal form it is .4375

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3 years ago

A human gene carries a certain disease from the mother to the child with a probability rate of 42%.That is, there is a 42% chanc

soldi70 [24.7K]

Answer:

Option B.

Step-by-step explanation:

It is given that there is a 42% chance that the child becomes infected with the disease.

Let A be the event that the child becomes infected with the disease.

$P(A)=42%=0.42$

A' be the event that the child is not infected.

$P(A')=1-P(A)=1-0.42=0.58$

Assume that the infections of the three children are independent of one another.

Let X be the number of children get the disease from their mother.

The probability that all three children are free from disease is

$P(X=0)=P(A')\cdot P(A')\cdot P(A')=0.58\cdot 0.58\cdot 0.58=0.195112$

We need to find the probability that at least one of the children get the disease from their mother.

$P(X\ge 1)=1-P(X=0)$

$P(X\ge 1)=1-0.195112$

$P(X\ge 1)=0.804888$

$P(X\ge 1)\approx 0.805$

The probability that at least one of the children get the disease from their mother is 0.805.

Therefore, the correct option is B.

3 0

4 years ago