Is there supposed to be an x before 4x?
The answer to that would be D!
(5,5) - (1,5) = (4,5) is the answer
Answer:
The first set of consecutive even integers equals (8 , 6)
The second set is ( - 8 and - 6) which also works.
Step-by-step explanation:
Equation
(x)^2 + (x + 2)^2 = (x)(x + 2) + 52 Remove the brackets on both sides
Solution
x^2 + x^2 + 4x + 4 = x^2 + 2x + 52 Collect the like terms on the left
2x^2+ 4x+ 4 = x^2 + 2x + 52 Subtract right side from left
2x^2 - x^2 + 4x - 2x + 4 - 52 = 0 Collect the like terms
x^2 + 2x - 48 = 0 Factor
(x + 8)(x - 6) = 0
Answer
Try the one you know works.
x - 6 = 0
x = 6
Therefore the two integers are 6 and 8
6^2 + 8^2 = 100
6*8 + 52 = 100
So 6 and 8 is one set of consecutive even numbers that works.
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What about the other set.
x + 8 = 0
x = - 8
x and x + 2
- 8 and -8 + 2 = - 8, - 6
(- 8 )^2 + (- 6)^2 = 100
(-8)(-6) + 52 = 100
Both sets of consecutive numbers work.
<h3>
Answer:</h3>
infinite solutions
<h3>
Step-by-step explanation:</h3>
Add the two equations.
... (-4x) + (y) = (y +3) +(-4x -3)
Add 4x -y to both sides.
... -4x +y +4x -y = -4x +y +4x -y
... 0 = 0 . . . . . true for all values of x (or y)
Both equations describe the same line.
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The graph shows the first equation as a red line. The second equation is shown using a "blue dot" texture, so you can see it overlays the red line.
