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Goryan [66]
3 years ago
13

A tropical species of mite named archegozetes longisetosus is the record holder for the strongest insect in the world. It can li

ft up to 1.182 • 10^3 times it's own weight
If you were as strong as the insect, explain how you could find how many pounds you could lift
Mathematics
2 answers:
horrorfan [7]3 years ago
7 0

The first thing we have to do is to measure your weight using a weighing scale.

Suppose your weight is 130 pounds, therefore you can lift:

<span>130 pounds * 1.182 • 10^3 = = 153,660 pounds or 1.537 x 10^5 pounds</span>

lianna [129]3 years ago
4 0

Answer:

Step-by-step explanation:

It is given in the question that insect can lift up to 1.182×10³ times of it's own weight.

In other words,

Weight lifted by the insect = 1.182 × 10³×(weight of the insect)

If I were as strong as the insect then this formula will be the same

Weight lifted by me = 1182 × (My weight)

If my weight at present = 132 pounds

Then I can lift the weight = 1182×132

                                         = 156024 pounds

                                         = 1.56\times 10^{5} pounds

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To solve this problem, we first have to convert 5 1/2 into an improper fraction. To do this, we multiply the unit (5) times the denominator (2) and then add the numerator (1) to the product, while still keeping the same denominator.


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Now, this makes our expression: 11/2 - 2/3


Next, we have to find a common denominator for 2 and 3 by finding their shared LCM, or least common multiple. In this case, the LCM is 6. This means that we are going to convert both of the fractions in the expression into fractions with the denominator 6, so that we can easily compute the subtraction.


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