The rate of descent is <em>164.64 meters / minute
</em><em />
<em />To get this answer you just divide the total number of meters descended by the total number of minutes passed.
<em>
</em>So:<em>
</em>922.02 ÷ 5.5 = 164.64
I hope this helped!! Have an amazing day! :D
6. It is asking you to find the surface area for this one:
1 litre = 0.001 cubic meters
15.4 litres = 0.0154 cubic meters
The volume of the cylinder has to be 0.0154m^3.
V = (pi(r)^2)h
0.0154 = (pi(r)^2)(1)
r^2 = 0.0154/pi
r = 0.07m
Surface Area of Circles on Bottom:
A = pi(r)^2
A = pi(0.07)^2
A = 0.0154
0.0154*2 = 0.0308m^2
Surface Area of Walls:
This will be the circumference of the circle times the height, since the walls are just like a big rectangle.
C = 2pi(r)
C = 2pi(0.07)
C = 0.44m
0.44*1 = 0.44m^2
Finally, add the two surface areas:
0.44 + 0.0308 = 0.47m^2
You will need 0.47m^2 of sheet metal to make this cylinder.
7. Find the volume of everything and just the graphite, and subtract the graphite’s volume from everything to get just the wood. The volume of a cylinder is pi((r)^2)h.
Everything:
Watch out for units, since the diameter is in mm and the length is in cm.
r = 3.5mm or 0.35cm
V = pi((0.35)^2)(14)
V = 5.34cm^3
Graphite:
r = 0.5mm or 0.05cm
V = pi((0.05)^2)(14)
V = 0.11cm^3
5.34 - 0.11 = 5.23cm^3
8. For this problem, it wants your answer in cm^3. Find the volume of one bowl and multiply it by 250:
r = 3.5cm
V = pi((3.5)^2)(4)
V = 153.94cm^3
153.94*250 = 38484.51cm^3 of soup needed.
I sure hope that I didn’t confuse you too much with all of my math gibberish (sorry). Please let me know if there is anything else that I can help with. Have a nice day
Answer:
Step-by-step explanation:
Answer: Area of cross section that is parallel to face CDHG is 432 cm².
Step-by-step explanation:
Since we have given that
There is a cross section that is parallel to face CDHG.
So, Length of cross section would be 36 cm
Width of cross section would be 12 cm.
So, Area of cross section would be
Hence, Area of cross section that is parallel to face CDHG is 432 cm².
15 is coefficient, a is a variable, 2 and -7 are like terms, 15a is a term and 2 and 7 are constants.
