Ask question

Ask question

All categories

2 years ago

10

15a+2-7 What are the terms, like terms, coefficients, and constants in this equation?

1 answer:

Elenna [48]2 years ago

5 0

15 is coefficient, a is a variable, 2 and -7 are like terms, 15a is a term and 2 and 7 are constants.

You might be interested in

What is the solution to this system of linear equations?

Luden [163]

Answer:

the answer is (5,-1)

Step-by-step explanation:

if you click on the image it will show you the image full screen

4 0

2 years ago

Read 2 more answers

Consider the function f(x) = 6sin(x^2) on the interval 0 ≤ x ≤ 3.

Vitek1552 [10]

<span> a) F' = 6 sin(x^2) = 0
x^2 = pi
x = sqrt(pi)

b) Fmax = F(1) + integral [1, pi] f(x) dx = 9.7743 </span>

4 0

2 years ago

Read 2 more answers

To fit in an existing frame, the length, x, of a piece of glass must be longer than 12 cm but not longer than 12.2 cm. Which ine

8090 [49]

The answer is A) <span>12 < x ≤ 12.2</span>

4 0

2 years ago

Read 2 more answers

Truth or Dare?<br> Have a nice day/night <3

denpristay [2]

Answer:

Truth plz

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Solve for y 16y^2-25=0

Pepsi [2]

Answer:

$\large\boxed{x=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}$

Step-by-step explanation:

$16y^2-25=0\\\\METHOD\ 1:\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\16=4^2\ \text{and}\ 25=5^2\ \text{therefore we have}\\\\4^2y^2-5^2=0\\\\(4y)^2-5^2=0\\\\(4y-5)(4y+5)+0\iff4y-5=0\ \vee\ 4y+5=0\\\\4y-5=0\qquad\text{add 5 to both sides}\\4y=5\qquad\text{divide both sides by 4}\\\boxed{y=\dfrac{5}{4}}\\\\4y+5=0\qquad\text{subtract 5 from both sides}\\4y=-5\qquad\text{divide both sides by 4}\\\boxed{x=-\dfrac{5}{4}}$

$METHOD\ 2:\\\\16y^2-25=0\qquad\text{add 25 to both sides}\\\\16y^2=25\qquad\text{divide both sides by 16}\\\\y^2=\dfrac{25}{16}\to y=\pm\sqrt{\dfrac{25}{26}}\\\\y=-\dfrac{\sqrt{25}}{\sqrt{16}}\ \vee\ x=\dfrac{\sqrt{25}}{\sqrt{16}}\\\\\boxed{y=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}$

7 0

2 years ago

Read 2 more answers