Explain the nature of documents that can be suitable for mergin

SINCE I CANT SEE IT KANG LOOK

jekas [21]

Answer:

Drama

Explanation:

: 0

7 0

3 years ago

Read 2 more answers

Python provides a special version of a decision structure known as the ________ statement, which makes the logic of the nested d

IrinaVladis [17]

Answer:

if-elif-else

Explanation:

In Python if condition is used to decide whether a statement or a block of statements is to be executed or not based on the condition, if the condition evaluates to true then the block of statements is executed and if the condition is false then it is not executed.

Sometimes we need to execute some other statement when the condition is false. For example

if (number1 <= number2)

print (number1, "is the smallest")

Lets suppose we want to print another statement if this condition evaluates to false. If the condition gets false then the following message should be displayed:

print(number 2, "is the smallest")

For this purpose else statement is used along with if statement to execute the block of code when the if condition evaluates to false.

if (number1 <= number2)

print (number1, "is the smallest")

else:

print(number 2, "is the smallest")

Now what if there are three numbers or more numbers to be compared in order to identify the smallest number from the given numbers. So in this case we have multiple options to be checked. else statement will not be enough a for else there can be at most one statement. With if elif else multiple conditions can be checked and if any of the condition evaluates to true then its block of code is executed and if none of the condition is true then the last else statement will be executed.

For example:

if (number1 <= number2) and (number1 <= number3):

print (number1, "is the smallest")

elif (number2 <= number1) and (number2 <= number3):

print (number1, "is the smallest")

else:

print (number3, "is the smallest")

In this example number1 is compared to number2 and number3. If both numbers are less than number1 then the program control goes to elif statement where number2 is compared to number1 and number3. if this condition is false too then the final else part will be printed which is that number3 is the smallest.

Take another example where there are more number of expressions to be checked.

val = 50

if (val == 40):

print ("value is 40")

elif (val== 35):

print ("value is 35")

elif (val == 25):

print ("value is 25")

elif(val==15):

print ("value is 15")

else:

print ("value is not present")

This will output the else part value is not present, because none of the condition evaluates to true.

7 0

4 years ago

Which of the following comments are correct? Select all that apply.

AnnZ [28]

Answer:

1/ hello

Explanation:

7 0

3 years ago

A database that is created and maintained using services such as Microsoft Azure or Amazon AWS is called a(n) _____ database.

Phantasy [73]

Answer:

It is called a cloud database

5 0

2 years ago

Program:

Mkey [24]

Answer:

See explaination

Explanation:

#method to print menu & handle user choice

def print_menu(input_str):

#printing menu

print('MENU')

print('c - Number of non-whitespace characters')

print('w - Number of words')

print('f - Fix capitalization')

print('r - Replace punctuation')

print('s - Shorten spaces')

print('q - Quit\n')

#getting choice

choice=input('Choose an option: ').lower()

#identifying choice

if choice=='c':

#displaying number of non white space chars in input_str

print('Number of non-whitespace characters:',get_num_of_non_WS_characters(input_str))

elif choice=='w':

#displaying number of words in input_str

print('Number of words:',get_num_of_words(input_str))

elif choice=='f':

#fixing capitalization and getting updated string and count of values capitalized

input_str,count=fix_capilization(input_str)

#displaying results

print('Number of letters capitalized:',count)

print('Edited text:',input_str)

elif choice=='r':

#replacing punctuation, displaying updated text

input_str=replace_punctuation(input_str)

print('Edited text:', input_str)

elif choice=='s':

#shortening spaces and displaying updated text

input_str = shorten_space(input_str)

print('Edited text:', input_str)

#returning choice and input_str

return choice,input_str

#returns the number of non white space chars in input_str

def get_num_of_non_WS_characters(input_str):

count=0

#looping through each character in input_str

for i in input_str:

if not i.isspace():

#i is not a space

count+=1

return count

#returns the number of words in input_str

def get_num_of_words(input_str):

#splitting words into list of tokens by space

words=input_str.split(' ')

count=0

#counting all non empty strings in words list

for i in words:

if len(i)>0:

count+=1

return count

#method to fix capitalization and return updated string and count of letters updated

def fix_capilization(input_str):

count=0

beginning=True #starting letter should be capitalized

result=''

for i in input_str:

if beginning and i.isalpha():

#start of a sentence and i is alphabetic

if i.islower():

#converting i to upper case, incrementing count

i=i.upper()

count+=1

result+=i

#not start of a sentence

beginning=False

elif i in '?.!':

#i is either ? or . or !, next letter should be capitalized

beginning=True

result+=i

else:

#any other character

result+=i

return result,count

#method to replace exclamation and semicolons with period and comma respectively

def replace_punctuation(input_str,exclamationCount =0,semicolonCount=0):

result=''

for i in input_str:

if i=='!':

i='.'

exclamationCount+=1

elif i==';':

i=','

semicolonCount+=1

result+=i

print('Punctuation replaced')

#displaying replaced values counts

print('exclamationCount:',exclamationCount)

print('semicolonCount:',semicolonCount)

return result

#removes all double or more spaces in input_str

def shorten_space(input_str):

input_str=input_str.strip()

result=''

prev=None

for i in input_str:

if prev==None:

result+=i

elif i==' ':

if prev != ' ':

result+=i

else:

result+=i

prev=i

return result

if __name__ == '__main__':

#getting input, printing it

input_str=input('Enter a sample text:\n')

print('\nYou entered:',input_str)

choice=' '

#looping until choice becomes q

while choice!='q':

choice,input_str=print_menu(input_str)

7 0

3 years ago