Answer:
see explaination
Explanation:
def words2number(s):
words = s.split()
numbers = ['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine']
result = ""
for word in words:
if word in numbers:
result += str(numbers.index(word))
return result
Answer:
Explanation:
The minimum depth occurs for the path that always takes the smaller portion of the
split, i.e., the nodes that takes α proportion of work from the parent node. The first
node in the path(after the root) gets α proportion of the work(the size of data
processed by this node is αn), the second one get (2)
so on. The recursion bottoms
out when the size of data becomes 1. Assume the recursion ends at level h, we have
(ℎ) = 1
h = log 1/ = lg(1/)/ lg = − lg / lg
Maximum depth m is similar with minimum depth
(1 − )() = 1
m = log1− 1/ = lg(1/)/ lg(1 − ) = − lg / lg(1 − )
Alexis was planning a dream vacation to Spain.
Alexis/She was especially looking forward to trying the local cuisine, including the famous Paella and Churros.
Alexis will have to practice the language
frequently to make it easier to speak with people.
Alexis/She has a long list of sights to see, including the El Prado museum and the beautiful park.
Hope this helps :)
Answer:
if/else is probably the most simple structure to use. It takes a lot of manually entering strings and what not though. Not sure if this is what you're wondering.
