What is the slope of the line whose equation is given by –2y + 38x = 38?
2 answers:
First you need to put the equation into slope-intercept form: y = mx+b
-2y + 38x = 38
-2y = -38x + 38
y = 19x - 19
m = slope
And the slope is 19.
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To get the slope of -2y+38x=38.
Let us convert to slope intercept form, that is y=mx+b
So, subtracting 38x from both sides, we get
-2y=-38x+38
Now, Divide by -2 on both sides, we get
y=(-38/-2)x+(38/-2)
y=19x-19
Slope, m=19
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