All categories

3 years ago

What is 6/7 of 2/3?

Mathematics

2 answers:

Scorpion4ik [409]3 years ago

8 0

Answer:

4/7

Step-by-step explanation:

6 times 2 = 12 and 7 times 3= 21

12/21

put the answer on simpliest form 4/7

horsena [70]3 years ago

3 0

6/7 ÷ 2/3 = 1 2/7 please I need some points

You might be interested in

Algebra 1 help!!!!!!!!!

baherus [9]

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the concept of expo functions.

f(x) = -8(2)^x - 12 ,

for f(0) ,here substitute x = 0

so we get as ,

==> f(0) = -8(2)^0 -12

==> f(0) = -8-12

==> f(0) = -20

hence, f(0) = -20

6 0

3 years ago

Read 2 more answers

The probability that a given urine sample analyzed in a pathology lab contains protein is 0.73 (event A). The probability that t

Ostrovityanka [42]

The right answer for the question that is being asked and shown above is that: "e.Events A and B are dependent because P(A|B) = P(A)." The probability that a sample contains protein, given that albumin is detected, is 1. The statement that is true is this e<span>vents A and B are dependent because P(A|B) = P(A).</span>

3 0

3 years ago

At Western University the historical mean of scholarship examination scores for freshman applications is 900. A historical popul

vampirchik [111]

Answer:

a) Null Hypothesis: $\mu =900$

Alternative hypothesis: $\mu \neq 900$

b) The 95% confidence interval would be given by (910.05;959.95)

c) Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d) $z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750$

Since is a bilateral test the p value is given by:

$p_v =2*P(Z>2.750)=0.0059$

Step-by-step explanation:

a. State the hypotheses.

On this case we want to check the following system of hypothesis:

Null Hypothesis: $\mu =900$

Alternative hypothesis: $\mu \neq 900$

b. What is the 95% confidence interval estimate of the population mean examination score if a sample of 200 applications provided a sample mean x¯¯¯= 935?

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=935$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=180$ represent the population standard deviation

n=200 represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=3278.222$

The sample deviation calculated $s=97.054$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$