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2 years ago

Which term best describes the statement given below? if a = b and b = c then a= c

Mathematics

2 answers:

Snezhnost [94]2 years ago

7 0

Answer:

Syllogism law

Step-by-step explanation:

Given:

a ⇒ b, and b ⇒ c, then a ⇒ c

This is a transitive property and it is also called syllogism law.

For example,

if it rains (a), then the cricket field will be wet (b), this means a ⇒b

If the cricket field wet(b), then the game will be cancelled(c), this means b ⇒c

if it rains (a), then the game will be cancelled(c), this means a ⇒ c

So it is a valid conclusion. This is called syllogism law.

Savatey [412]2 years ago

4 0

<span>Combinations. This is because in combinations the order does not matter

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3 years ago

The area of juans garden

mario62 [17]

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3 years ago

Help plz anyone ! <br><br> three consecutive integers have a sum of 78. find the integers.

Drupady [299]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Jane's salary is increased by 2% to $30396. How much was her salary before the rise?

harina [27]

_award brainliest if helped!

so 102% = 30396
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Her salary was $29800 before the rise

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3 years ago

Read 2 more answers

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

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2 years ago