Question

NO LINKS!! NO MULTIPLE CHOICE!!​

Answer 1

Answer:

Given points

• A = (2, 1)
• B = (4, 3)
• C = (5, 3)
• D = (6, 1)

Part (a)

See attached

Part (b)

Trapezoid

Part (c)

To dilate ABCD with a dilation center at (0,0) and a dilation factor of 4, multiply the x and y coordinates of ABCD by sf 4:

• A' = (8, 4)
• B' = (16, 12)
• C' = (20, 12)
• D' = (24, 4)

Part (d)

$\begin{aligned}\textsf{Area of Trapezoid}& =\dfrac{1}{2}(a+b)h\\\implies \textsf{Area of A'B'C'D'}& =\dfrac{1}{2}((x_{D'}-x_{A'})+(x_{C'}-x_{B'}))(y_{B'}-y_{A'})\\& = \dfrac{1}{2}((24-8)+(20-16))(12-4)\\& = \dfrac{1}{2}(20)(8)\\& = 80\: \sf units^2\end{aligned}$