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3 years ago

Give your answer with an exponent

1 answer:

Klio2033 [76]3 years ago

5 0

5³*5^6=5^9
8^7/8²=8^5
9^7/9^11=1/9²
4^5^3=4^15

when multiplying like bases you add exponents. when dividing like bases you subtract exponents. when reasoning a number to a power then to another power you multiply exponents

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The millers are going to put a pool in their backyard this summer. The pool will have a depth of 5 feet, and the dimensions show

erica [24]

Answer:

D : 510 units

Step-by-step explanation:

NOTE:

Something to consider when solving problems like this is to break the large shape down into smaller, more managable shapes. So for this problem, you can break down this irregular shape into two rectangles. This will make solving problems similar to this easier in the future :)

WORK:

I broke down this shape into two rectangles with the following dimensions:

- 12 meters by 5 meters

- 3 meters by 14 meters

You also know that the depth has to be 5 feet (the problem itself did not account for differences in feet and meters, as when I converted the 5 feet to meters and solved that way, none of the answers were correct)

Using this information, you can now solve for the volume of each of the rectangles

12*5*5 = 300 units

3*14*5 = 210 units

Then, you simply add the two volumes together to find the total volume needed to fill the pool which equals

510 units

3 0

3 years ago

Which of these equations have no solution? Check all that apply.

dlinn [17]

First one simplifies to 2x + 6 = 2x + 7 which can't be true so this one has No Solution.
Same applies to the second equation ( 5x + 15 = 5x - 15) No solution

also the last one has no solution because it simplifies to 4x + 20 = 4x + 19

6 0

3 years ago

Can someone please explain how to do number 23 I have no idea how to do it.

taurus [48]

Ok so first equate all the three equations whether by substituting or by eliminating then choose the one das not the answer

3 0

3 years ago

Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

6 0

4 years ago

What statement makes the open sentence true ?

dedylja [7]

The answer is C. x=4

Explanation) 49 - 7 (4) = 21

7 (4) = 28

49 - 28 = 21

3 0

3 years ago

Read 2 more answers