Idk tbh man I think sumbody else will answer
Answer:
Q1. x= 18, y=59
Q2. m∠J= 56°
Step-by-step explanation:
Q1. (3x +5)°= y° (base ∠s of isos. △)
y= 3x +5 -----(1)
(3x +5)° +y° +(4x -10)°= 180° (∠ sum of △)
3x +5 +y +4x -10= 180
7x +y -5= 180
7x +y= 180 +5
7x +y= 185 -----(2)
Substitute (1) into (2):
7x +3x +5= 185
10x= 185 -5
10x= 180
x= 180 ÷10
x= 18
Substitute x= 18 into (1):
y= 3(18) +5
y= 59
Q2. (5x -13)°= (3x +17)° (base ∠s of isos. △)
5x -13= 3x +17
5x -3x= 17 +13
2x= 30
x= 30 ÷2
x= 15
∠LKJ
= 3(15) +17
= 62°
∠KLJ= 62° (base ∠s of isos. △)
m∠J
= 180° -62° -62° (∠ sum of △JKL)
= 56°
Answers:
- Exactly 25%
- median = 450
- Not enough info (see below)
- IQR = 24
- IQR = 192
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Explanations:
- By definition, the quartiles split the data into four equal parts. The first quartile (Q1) will have 25% of the data below it.
- The second quartile is the exact same value as the median. This is because the median splits the data into two equal halves, i.e. is at the midpoint.
- There's not enough info. We can determine that 25% of the company makes more than $60,000, but we don't know how many people total work at the company. This info is missing.
- Subtract the third and first quartiles (Q3 and Q1) to get the interquartile range (IQR). So IQR = Q3 - Q1 = 45-21 = 24
- Same idea as the previous problem. IQR = Q3 - Q1 = 316.5 - 124.5 = 192
Answer:
Answer: 19.2
Step-by-step explanation:
To calculate percentage, multiply the number 80 by 0.24, and the answer is 19.2.
Answer:
Step-by-step explanation:
Let the number of computers sold by Joe be represented by variable X
If Jonathan sold 5 times as many computers , it means he sold 5 times X= 5X
Total number of computers sold by both Jonathan and Joe = 78
Hence, X+5X =78
= 6X = 78
Divide both sides by 6 to solve for X;
X = 78/6
X = 13
And 5X = (5* 13) = 65
Therefore, Jonathan sold 65 computers while Joe sold 13
