The common factor of 45 and 6 is 3
The common factor of
m and m^5 is m
Together the GCF is 3m
Answer:
<h3>p = 131.25</h3>
Step-by-step explanation:
The variation p varies directly with T is written as
p = kT
where k is the constant of proportionality
To find p when T =500 we must first find the formula for the variation
That's
when p = 105 and T = 400
105 = 400k
Divide both sides by 400
<h3>
</h3>
So the formula for the variation is
<h2>
</h2>
when
T = 500
Substitute it into the above formula
That's
Simplify
The final answer is
<h3>p = 131.25</h3>
Hope this helps you
Dr /dt = 7
A = pi r^2
dA / dr = 2pir
dA/dt = dA/dr * dr/dt = 2pir * 7 = 14pir
when r = 12 rate of change of the area = 14*pi*12 = 168pi
= 527.79 cm^2 / minute to nearest hundredth
32 and 34? I'm sure that's what the questing is asking. Hopefully that helped. Someone correct me if I'm wrong.
Answer:
Coordinate Q is (0.8, 0.7)
Step-by-step explanation:
We are told that the coordinates of point Pare (0.6,0.1).
This means that along the x-axis, x = 0.6 and along the y-axis, y = 0.1.
Now, by inspection of the graph, we can see that when we count boxes from the origin to the point P, we have 6 boxes. Thus, each box corresponds to 0.1. So, for point Q, from the origin to that point, on the x-axis, we have 8 boxes. Since one box = 0.1, then the x - value of Coordinate Q is 0.8.
On the y - axis, we see that we have one box from the origin up for the corresponding y-value of coordinate P.
This means that one box is 0.1.
For coordinate Q, we will count 7 boxes. Thus, y-value of coordinate Q is 0.7.
Thus,coordinate Q is (0.8, 0.7)
