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goldenfox [79]
4 years ago
7

In the U.S. Senate, there are 21 members on the Committee on Banking, Housing, and Urban Affairs. Nine of these 21 members are s

elected to be on the Subcommittee on Economic Policy. How many different committee structures are possible for this subcommittee?
Mathematics
1 answer:
Elenna [48]4 years ago
8 0

Answer:

₂₁C₉ = 293930

Step-by-step explanation:

9 members out of 21 senators will be selected on the subcommittee on Economy Policy

So we are in case of combinations of 21 people in groups of 9

₂₁C₉ =21! /( (21-9)!) *9! ⇒21*20*19*18*17*16+15*14*13*12! /(21-9)! *9!

 =21*20*19*18*17*16*15*14*13/ 9! ⇒    = 19*2*17*15*14*13/6 ⇒ =293930

   

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The area of the triangle below is 6.12 square feet. What is the length of the base?
Amanda [17]

Answer: 3.6

Step-by-step explanation:

½bh = 6.12

½ × 3.4 × b = 6.12

b = 6.12/ 1.7

4 0
2 years ago
A fitness center is interested in finding a 90% confidence interval for the mean number of days per week that Americans who are
Blababa [14]

Answer:

A. Normal

B. Between 2.078 and 2.722 visits.

C. About 90 percent of these confidence intervals will contain the true population mean number of visits per week and about 10 percent will not contain the true population mean number of visits per week.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

Question A:

By the Central Limit Theorem, normal.

Question B:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645\frac{2.9}{\sqrt{219}} = 0.322

The lower end of the interval is the sample mean subtracted by M. So it is 2.4 - 0.322 = 2.078 visits

The upper end of the interval is the sample mean added to M. So it is 2.4 + 0.322 = 2.722 visits.

Between 2.078 and 2.722 visits.

Question c:

90% confidence level, so 90% will contain the true population mean, 100 - 90 = 10% wont.

About 90 percent of these confidence intervals will contain the true population mean number of visits per week and about 10 percent will not contain the true population mean number of visits per week.

5 0
3 years ago
A savings account accrues interest at a rate of 3.0% yearly. If someone opens an account with $2,500, how much money would the a
Sauron [17]
3\%=\frac{3}{100}=0,03\\\\
First\ year:2500+2500*0,03=2500+75=2575\\\\Second\ year:\ 2575+2575*0,03=2575+77,25=2652,25\\\\Third\ year:\ \ 2652,25+2652,25*0,03=2652,25+79,5675=\\\\2731,8175\\\\ Fourth\ year: 2731,8175+2731,8175*0,03=2731,8175+81,954525\\\\=2813,772025\\\\Fifth\ year:\ 2813,772025+2813,772025*0,03=\\\\2813,772025+84,41316075=2898,18518575\$
5 0
4 years ago
you are putting grass down in your backyard. the total area is 51 feet squared. the length of your yard is 10.2 feet. how wide i
Nat2105 [25]

5 feet wide because a=l*w l being length and w being width.

we have 2 parts of the equation: 51=10.2*w so we divide both sides by 10.2 giving us 5=w  

6 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!
Lelechka [254]

Answer:

Step-by-step explanation:

(8x²-18x+10)/(x²+5)(x-3)

express the expression as a partial fraction:

(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +bx+c/x²+5

both denominator are equal , so require only work with the nominator

(8x²-18x+10)=(x²+5)A+(x-3)(bx+c)

8x²-18x+10= x²A+5A+bx²+cx-3bx-3c

combine like terms:

x²(A+b)+x(-3b+c)+5A-3c

(8x²-18x+10)

looking at the equation

A+b=8

-3b+c=-18

5A-3c=10

solve for A,b and c (system of equation)

A=2 , B=6, and C=0

substitute in the value of A, b and c

(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +(bx+c)/x²+5

(8x²-18x+10)/[(x^2+5)(x-3)] = 2/x-3 + (6x+0)/(x²+5)

(8x²-18x+10)/[(x^2+5)(x-3)] =

<h2>2/(x-3)+6x/x²+5</h2>

(4x+2)/[(x²+4)(x-2)]

(4x+2)/[(x²+4)(x-2)]= A/(x-2) + bx+c/(x²-2)

(4x+2)=a(x²-2)+(bx+c)(x-2)

follow the same step in the previous answer:

the answer is :

<h2>(4x+2)/[(x²+4)(x-2)]= 5/4/(x-2) + (3/2 -5x/4)/(x²+4)</h2>

8 0
3 years ago
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