We can solve this system of equation by reduction method.
d+e=15
-d+e=-5
-------------------
2e=10 ⇒e=10/2=5
-(d+e=15)
-d+e=-5
-----------------
-2d=-20 ⇒d=-20/-2=10
therefore: d=10; e=5
Answer: d.(10,5)
This solution to this problem is predicated on the fact that the circumference is just:
. A straight line going through the center of the garden would actually be the diameter, which is well known to be two times the radius of the circle, so we can say that the circumference is just:

So, solving for both the radius and the diameter gives us:

So, the length of thes traight path that goes through the center of the guardain is just
, and we can use the radius for the next part of the problem.
The area of a circle is
, which means we can just plug in the radius and find our area:

So, we have found our area(
) and the problem is done.
Answer: (-1,1,-3) + 7 x t x (3,-2,-8)/
Step-by-step explanation:
The parametric vector equation for the position of particle is given as:
We have P= (-1,1-3)
Q= (-4,4,5)
So PQ vector= (-1+4,1-3, -3-5)
PQ = (3,-2,-8)
Magnitude of this vector= 
Magnitude= 
So unit vector= (3, -2, -8)/
Now the equation is as:
P + 7 x t x unit vector = (-1,1,-3) + 7 x t x (3,-2,-8)/
Answer:
The answer is "Option C"
Step-by-step explanation:
please find the complete question in the attached file:
Its ratio of samples by Johns Hopkins will be about the equivalent than those from Ohio State because sample varying depending on the sample, each of them would have the same variability also like the amount, that's why he assumes the variance of sample sizing in the sample percentage p with both the hat above, relative to the confidence interval in Ohio State determined from its Johns Hopkins test.
Answer:
Step-by-step explanation:
area=(20 ×20)÷2=200 sq . units