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zmey [24]
3 years ago
13

A(2,4) and B(6,8) . find the midpoint of M

Mathematics
2 answers:
inysia [295]3 years ago
8 0
8-4/6-2 = 2/4 = 1/2
11111nata11111 [884]3 years ago
5 0
Here's the midpoint formula:

M[(x1+x2)/2 , (y1+y2)/2]

sub your points into this formula and you get: 

M[(2+6)/2 , (4+8)/2] 
 =[8/2 , 12/2]
 =[4 , 6]

therefore, the midpoint M of A(2,4) and B(6,8) is M(4,6)

let me know if you have any other questions regarding how the formula works or what I did

hope it helps :)
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If this line is parallel to the line you've just mentioned, it will have a gradient 2/3. We know this, because when we re-arrange the equation you've given us, we get...

y-4=\frac { 2 }{ 3 } \left( x-3 \right) \\ \\ y-4=\frac { 2 }{ 3 } x-2\\ \\ y=\frac { 2 }{ 3 } x-2+4\\ \\ y=\frac { 2 }{ 3 } x+2

So, at the moment, our parallel line looks like this...

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However, you mentioned that this line passes through the point Q(1, -2). If this is the case, for the line (almost complete) above, when x=1, y=-2. With this information, we can figure out the constant of the line we want to find.

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Therefore:

C = - 2 - (2/3)

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This means that the line you are looking for is:

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3 years ago
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jonny [76]
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