PLEASE HELP! I’ll give brainliest!
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
given ,
equation y=ax²+bx+c
passing through points (1,6), (3, 20), and (−2,15).
then these points will satisfy the equation
at (1,6)
y = a x²+b x+c
6 = a(1)² + b (1) + c
a + b + c = 6------(1)
at (3 , 20)
y = a x²+b x+c
20 = a(3)² + b (3) + c
9 a + 3 b + c = 20------(2)
at (−2,15)
y = a x²+b x+c
15 = a(-2)² + b (-2) + c
4 a -2 b + c = 15------(3)
solving equation (1),(2) and (3)
a = 6 - b - c
9 (6 - b - c)+ 3 b + c = 20
6 b + 7 c = 34-------(4)
4 (6 - b - c) -2 b + c = 15
2 b + c = 3----------(5)
on solving equation (4) and (5)
Step-by-step explanation:
Given the following question:
First thing we need to keep in mind is the fact that this graph is indeed a circle. We know this because we are adding two cubic roots to each other which makes the graph a circle. We know the two separate functions are cubic roots because they each have an exponent of two. Not only is this function whose graph is a circle, but the midpoint of this circle is (2,2).
Hope this helps.
