Answer:
λN N(0) = 6
N(t) = N₀e^(λt)
Applying the inital value condition
N(t) = 6e^(λt)
Step-by-step explanation:
Summarizing the information briefly and stating the variables in the problem.
t = time elapsed during the decay
N(t) = the amount of the radioactive substance remaining after time t
λ= The constant of proportionality is called the decay constant or decay rate
Given the initial conditions
N(0) = N₀ = 6
The rate at which a quantity of a radioactive substance decays (
) is proportional to the quantity of the substance (N) and λ is the constant of proportionality is called the decay constant or decay rate :
λN
N(t) = N₀e^(λt) ......equ 1
substituting the value of N₀ = 6 into equation 1
N(t) = 6e^(λt)
5×2=10 1×10 those two factors equal 10. O cant think of anymore
Answer:
17
Step-by-step explanation:
I believe the answer is 17.
Simplify
17
=17
Now,
Consider point O at zero on the number line.
Mark a point A such at number 4 such that OA= 4
Draw a perpendicular AB at point A of unit length.
Join AB
Taking radius of length AB draw an arc to intersect the number line at C.
Finally, OC=\sqrt{17}
Thus proving the answer is 17 or 