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torisob [31]
4 years ago
6

The amount of money, in dollars, in a savings account after x years is given by M(x) = 10,000(1.03)x. What does the value 1.03 r

epresent?
A) The original deposit was $103.
B) There is a 3 percent increase in the savings account each year.
C) The savings account earns $103 interest per month.
Eliminate
D) There is a 103 percent increase in the savings account each year.
Mathematics
2 answers:
mr Goodwill [35]4 years ago
7 0

Answer:

Option B) There is a 3 percent increase in the savings account each year.

Step-by-step explanation:

we have

M(x)=10,000(1.03^x)

This is a exponential function of the form

y=a(b^x)

where

M(x) represent the amount of money in a saving account

x represent the number of years

a is the original deposit (y-intercept)

b is the base

r is the rate or percent increase

b=(1+r)

The percent increase per year is the base of the exponential function decreased by 1.

so

r=b-1

In this problem we have

a=\$10,000 ---> original deposit

b=1.03\\r=1.03-1=0.03=3\%

Therefore

The percent increase per year is 3%

Olegator [25]4 years ago
4 0

Answer:

B)  

There is a 3 percent increase in the savings account each year.

Step-by-step explanation:

There is a 3 percent increase in the savings account each year.  

M(x) = 10,000(1.03)x → 1.03 = 103% = 100% + 3% growth → This is a 3 percent increase each year.

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how much money has to be invested at 5.9% interest compounded continuously to have 15,000 after 12 years?
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Hi there

The formula is
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