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3 years ago

Name the property the equation illustrates.

Mathematics

2 answers:

Maslowich3 years ago

6 0

I think it is the associative property of Addition

Damm [24]3 years ago

5 0

it is the associative property of Addition

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Consider an espresso stand with a single barista. Customers arrive at the stand at the rate of 28 per hour according to a Poisso

Snowcat [4.5K]

Answer:

The average number of customers in the system is 3.2

Step-by-step explanation:

The average number of customes in the system is given by:

$L = \frac{\lambda^{2}}{\mu(\mu - \lambda)}$

In which

$\lambda$ is the number of arirvals per time period

$\mu$ is the average number of people being served per period.

The number of arrivals is modeled by the Poisson distribution, while the service time is modeled by the exponential distribution.

Customers arrive at the stand at the rate of 28 per hour

This means that $\lambda = 28$

Service times are exponentially distributed with a service rate of 35 customers per hour.

This means that $\mu = 35$ . So

The average number of customers in the system (i.e., waiting and being served) is

$L = \frac{\lambda^{2}}{\mu(\mu - \lambda)}$

$L = \frac{28^{2}}{35(35 - 28)} = 3.2$

The average number of customers in the system is 3.2

4 0

3 years ago

Jenny says the two expressions 7a – 4 + 3a - 6 and 4a – 10 are<br> equivalent? Is she correct?

zavuch27 [327]

Answer:

no she is wrong

Step-by-step explanation:

7a-4+3a-6= 10a-10 therefore they are not equal

5 0

3 years ago

Read 2 more answers

Which is an equation of the line that passes through the point

Allisa [31]

Answer:

y = $\frac{1}{2} x$ +3

Step-by-step explanation:

4 0

3 years ago

Pratap puri rowed 10 miles down a river in 2 hours, but the return trip took him 2 and one half hours. Find the rate pratap can

N76 [4]

Answer:

<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>

Step-by-step explanation:

Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.

We know that, $Speed = \frac{Distance}{Time}$

So, the <u>speed of Pratap with the current</u> will be: $(\frac{10}{2})miles/hour = 5$ miles/hour

and the <u>speed of Pratap against the current</u> will be: $(\frac{10}{2.5})miles/hour = 4$ miles/hour.

Suppose, the rate of Pratap in still water is $x$ and the rate of current is $y$ .

So, the equations will be........

$x+y= 5 .............................. (1)\\ \\ x-y=4 .............................. (2)$

Adding equation (1) and (2) , we will get......

$2x=9\\ \\ x=\frac{9}{2}= 4.5$

Now, plugging this $x=4.5$ into equation (1), we will get.....

$4.5+y=5\\ \\ y=5-4.5 =0.5$

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.

6 0

3 years ago

Brice has $1200 in the bank. He wants to save a total of $3000 by depositing $40 per week from his paycheck. Write and use an eq

Anon25 [30]

$$3000-$1200=$1800

take $1800÷$40=45

<h3>answ=45 weeks</h3>

6 0

2 years ago