Step-by-step explanation:
Let's solve for c.
5c=d
Step 1: Divide both sides by 5.
5c
5
=
d
5
c=
1
5
d
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
y^2 +6^2 = 12^2
y^2 +36 = 144
y^2 = 108
sqrt(108) = 10.392 = 6sqrt(3)
Answer is B 6sqrt(3)
Answer:
In Mathematics Geometry,<em> lateral face</em> is said be the side of a 3D-figure in that is not a base.
Please check the attached figure to visual the concept.
Step-by-step explanation:
In Mathematics Geometry,<em> lateral face</em> is said be the side of a 3D-figure in that is not a base.
The faces in in a prism or pyramid which are not bases are basically the lateral faces.
For example, the lateral faces are basically parallelograms in Triangular prism which are not the bases.
Please check the attached figure to visual the concept.
The hypotenuse would be square root of 41
