9514 1404 393
Answer:
(a) a^4/(4b^2)
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)/(a^c) = a^(b-c)
a^-b = 1/a^b
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Your expression simplifies as follows.

Z(x) = 6x^3 + bx^2 - 52x + 15
z(2) = 6(2)^3 + b(2)^2 - 52(2) + 15 = 6(8) + 4b - 104 + 15 = 4b - 41 = 35
4b = 35 + 41 = 76
b = 76/4 = 19
Thus, z(x) = 6x^3 + 19x^2 - 52x + 15
Since z(-5) = 0, x + 5 is a factor of z(x)
Dividin z(x) by x + 5 gives 6x^2 - 11x + 3 = 6x^2 - 2x - 9x + 3 = 2x(3x - 1) - 3(3x - 1) = (2x - 3)(3x - 1) = 0
x = 3/2 and x = 1/3
Therefore, the zeros of z(x) are -5. 1/3 and 3/2
Answer:
nvm, I made a mistake
Step-by-step explanation:
3, 5 and 7 are three prime numbers. The least common multiple of prime numbers is simply the product of the numbers themselves: so you have

Answer:
Step-by-step explanation:
because the two line segments are the same length-->
12+10-x=18
x=22-18=4