1 + tan ² Ф=sec²Ф
1+(12/5)²=sec²Ф
169/25=sec² Ф
sec Ф=⁺₋√(169/25)=⁺₋13/5
sec Ф=1/cos Ф ⇒cosФ=1/sec Ф
cos Ф>0 ⇔ sec Ф>0 ⇔ sec Ф=+ 13/5
cos Ф=1/secФ
cos Ф=1 / 13/5=5/13
we can calculate the sin Ф, with this method.
sin²Ф + cos²Ф=1 ⇒ sin Ф=⁺₋√(1-cos² Ф)
sin Ф=⁺₋√[1-(5/13)²]=⁺₋12/13
like cos Ф>0 and tan Ф>0 ⇒ sin Ф>0 ⇒sin Ф=12/13
answer: d.12/13
other method
tan Ф=sin Ф / cos Ф
12/5=sin Ф / 5/13
sin Ф=(12/5)*(5/13)=12/13
answer: d.12/13
Answer:
8:14, 12:27, 40:70
Step-by-step explanation:
Answer:
x = 10
y = 13
Step-by-step explanation:
Answer:
Step-by-step explanation:
Part A:
The interquartile range is approximately 10
Part B:
The difference between the median values for each data set is approximately 6
Part C:
i) More widely distributed and concentrated to the beginning of the month
The better measure of the center for the male dataset is the median
ii) The skewed distribution
The mean is the better measure of center for the dataset
Part D;
A possible reason for the outlier is by chance
Answer:
x = 3
Step-by-step explanation:
3(10-x)=21
30-3x=21
-30 -30
-3x=-9
x=3
