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stira [4]
3 years ago
12

Peter is working for an hourly wage of $12. If he worked for 20 hours last week, what is his gross pay?

Mathematics
2 answers:
Ghella [55]3 years ago
8 0

Answer:

$240.

Step-by-step explanation:

We have been given that Peter is working for an hourly wage of $12. He worked for 20 hours last week.

Since gross pay is the income before any tax deductions. To find Peter's gross pay, we need to multiply his hourly wages by number of hours we worked.

\text{Peter's gross pay}=\frac{\$12}{\text{ hour}}\times 20\text{ hours}}

\text{Peter's gross pay}=\$12\times 20

\text{Peter's gross pay}=\$240

Therefore, Peter's gross salary last week was $240.

exis [7]3 years ago
6 0
If Peter worked 20 hours last week and makes $12 a hour, his gross pay was $240. 

12 x 20 = 240. 
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What is the simplified expression for 2 (x minus 5)?
sp2606 [1]

Answer:

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Step-by-step explanation:

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1,5,9,13 generalize the pattern by finding the nth term
ladessa [460]

Answer:

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Step-by-step explanation:

a1 = 1, a2 =5, a3 = 9, a4= 13,... an= ?

we see that each term is getting bigger so usually that will happen because of addition or multiplication-in our case add 4 to previous term

a1 = 1,

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3 years ago
If 2(x + 3) = x + 10, then x equals what
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Answer:

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Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. You need to apply the Distributive property on the left member of the equation:

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What is the correct first step to solve this system of equations by elimination?
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\bold{\huge{\pink{\underline{ Solution }}}}

\bold{\underline{ Given }}

  • <u>We </u><u>have </u><u>given </u><u>two </u><u>linear </u><u>equations </u><u>that</u><u> </u><u>is </u><u>2x </u><u>-</u><u> </u><u>3y </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>and </u><u>x</u><u> </u><u>+</u><u> </u><u>3y </u><u>=</u><u> </u><u>1</u><u>2</u><u> </u><u>.</u>

\bold{\underline{ To \: Find }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y </u><u>by </u><u>elimination </u><u>method</u><u>. </u>

\bold{\underline{ Let's \: Begin }}

\sf{ 2x - 3y = -6 ...eq(1)}

\sf{ x +  3y = 12 ...eq(2)}

<u>Multiply </u><u>eq(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>by </u><u>2</u><u> </u><u>:</u><u>-</u>

\sf{ 2( x + 3y = 12 )}

\sf{ 2x + 6y = 24 }

<u>Subtract </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>from </u><u>eq(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>

\sf{ 2x + 6y -( 2x - 3y) = 24 -(-6)}

\sf{ 2x + 6y - 2x + 3y = 24 + 6 }

\sf{   9y = 30 }

\sf{   y = 30/9}

\sf{\red{ y = 10/3}}

<u>Now</u><u>, </u><u> </u><u>Subsitute</u><u> </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

\sf{ 2x - 3(10/3) = -6 }

\sf{ 2x - 10 = -6 }

\sf{ 2x  = -6 + 10}

\sf{ x  = 4/2}

\sf{\red{ x  = 2}}

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