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dedylja [7]
2 years ago
8

Solve the following equation. Then place the correct number in the box provided.

Mathematics
2 answers:
Feliz [49]2 years ago
6 0

Answer:

x=3 because you have to make it = the other side

kenny6666 [7]2 years ago
5 0
X=0 because if you add 7+0+2 it will equal 9
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Maricell, the fruit juggler, bought 0.24 pounds of apples and 3.1 pounds of oranges. How many pounds of fruit did Maricell buy?
frosja888 [35]
The answer is 3.34 pounds also the estimate would be 3 pounds.

3 0
3 years ago
Carlos says that 17.43 divided by 100 is the same as 174.3 times 0.01<br> Is he correct? Explain
Leokris [45]

Answer:

Is not correct

Step-by-step explanation:

Step 1

Find 17.43 divided by 100

\frac{17.43}{100}=0.1743

Step 2

Find 174.3 times 0.01

174.3*0.01=\frac{174.3}{100}=1.743

Compare

0.1743\neq 1.743

7 0
3 years ago
Read 2 more answers
Instructions: Select the correct answer.
zepelin [54]
= 18 1/5 + 22 2/5 + 40 1/5
answer is D. last one
5 0
3 years ago
HELP PMEASR GCF show work!! 20 points
damaskus [11]
It’s either just 2xy or it’s 2xy(x+2)(x-4)
5 0
2 years ago
A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for
Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

\implies h=\frac{1}{w^2}

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

= 2\times \frac{1}{w^2}(w+2w)

=\frac{6w}{w^2}

=\frac{6}{w}  

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}

=2w^2+4w^2+\frac{12}{w}

=6w^2+\frac{12}{w}

Differentiating with respect to w,

C'(w) = 12w -\frac{12}{w^2}

Again differentiating with respect to w,

C''(w) = 12 + \frac{24}{w^3}

For maxima or minima,

C'(w) = 0

\implies 12w -\frac{12}{w^2}=0

\implies 12w^3 - 12=0

w^3-1=0\implies w = 1

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0
3 years ago
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