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marusya05 [52]
3 years ago
6

Need help like last time do the same thing

Mathematics
1 answer:
pashok25 [27]3 years ago
3 0
5) 8/6=4/3=1 1/3

He collected 1 1/3 

6) 60/10=6

They sold 6 cats per week

7) 90/10=9

He/she installed 9 sheets per minute.
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A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h
julsineya [31]

Answer:

a.P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

b. E(x) = 0.3

c. S(x)=0.5196

d. E=5,000

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\

For binomial distribution:

E(x)=np\\S(x)=\sqrt{np(1-p)}

Therefore, the company can expect to win 0.3 bids and it is calculated as:

E(x) = np = 3*0.1 = 0.3

Additionally, the standard deviation of the number of bids won is:

S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196

Finally, the probability to won 1, 2 or 3 bids is equal to:

P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001

So, the expected profit for the company is equal to:

E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

5 0
3 years ago
Is 4.64 prime or composite
AlladinOne [14]

Answer:

Therefore all numbers that end with five and are greater than five are composite numbers. The prime numbers between 2 and 100 are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89 and 97.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A sample of iron ore has a density of 7.87 what is its mass? Show all of your work. If it measures 7.5 cm x 2.53 em x 7.15 cm,
mr_godi [17]

Answer:

Mass=1068gr

Step-by-step explanation:

Volume= 7.5 cm x 2.53 cm x 7.15 cm=135.7cm^3

Density=7.87gr/cm^3

Mass=Density*Volume=135.7*7.87=1068gr

7 0
3 years ago
Please help as soon as possible <br>I WILL MARK YOU AS BRAINLIEST ​
astra-53 [7]

Answer:

Last choice

Step-by-step explanation: Subtract 11 and then divide by 3. A would be greater than -2 and last choice shows that

3 0
3 years ago
Solve for t in terms of q, r, and s.<br> r = sqt<br> t=
mars1129 [50]

Answer:

t=r/(sq)

Step-by-step explanation:

r=sqt

=> r/(sq)=t

5 0
3 years ago
Read 2 more answers
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