Angle KMQ and angle RNL are on apposite sides of the transversal and between above and below (exterior to) the parallel lines, so they are alternate exterior angles. Theorem - Alternate exterior angles formed by parallel lines and a transversal have the same measure.
Answer:
x= -8 , y = 5
x= 25/4 , y = 1/4
Step-by-step explanation:
substitute first eqn into the second eqn:
(7 - 3y)^2 -y^2 = 39
49 - 42y + 9y^2 - y^2 = 39
8y^2 - 42y +10 =0
4y^2 - 21y + 5 = 0
(4y-1) (y-5) = 0
y= 1/4 , 5
when y=1/4
x = 7- 3/4
=25/4
when y= 5
x = 7- 15
= -8
I believe it's 12 because 5*16=80. So, then you would subtract 4 from 16 and gat 12.
Take into account, that in general, a cosine function of amplitude A, period T and vertical translation b, can be written as follow:
In the given case, you have:
A = 4
T = 3π/4
b = -3
By replacing you obtain:
Hence, the answer is:
f(x) = 4cos(8/3 x) - 3
the scale factor used in Emily scale drawing is K = 1.63 mm/m
<h3>
What scale did Emily use?</h3>
We know that Emily drew a scale drawing of a house and its lot.
In the scale drawing, the back patio is 42 millimeters long, and we know that the actual patio is 27 meters long.
Then the scale relates the measures 44mm and 27 meters, such that if the scale is K, we can write:
K*27m = 44mm
Solving for K, we can write:
K = (44/27) mm/m = 1.63 mm/m
So the scale factor used in Emily's scale drawing is K = 1.63 mm/m
If you want to learn more about scale factors:
brainly.com/question/25722260
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