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german
3 years ago
7

What is the place value of the number 1 in the number 1,376,948

Mathematics
1 answer:
kotegsom [21]3 years ago
4 0
The answer is 1000000.

First off, we have to understand that the number is formed of ones,tens,hundreds,thousands etc.

Where ones is the first number from right to left, tens is the second, the list goes on. As they are named, they represent different value.

To find the value,we multiply the number with it places. For example, if 3 is in the tens,we multiply it by 10 making the value 30.

In this case, 1 is the millions, thus we will have to multiply the value by 1000000, making the place value 1000000.

Hope it helps!
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1+3+5+7+...+999 =

= 1+2+3+4+...+500

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= 2·(1+2+3+...+499) + 500

= 2·(499·500)/2 + 500

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= 500·(499 + 1)

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let f(x)= p+ 8/x-q. the line x=4 is a vertical asymptote to the graph of f. what is the value of q and p, if the y intercept is
svlad2 [7]

Answer:

The value of q and p is 4 and -24  respectively.

Step-by-step explanation:

Being f(x)=\frac{p+8}{x-q} , the line x=4 is a vertical asymptote to the graph of f(x).  The line r is an asymptote of a function if the graph of the function is infinitely close to the line r. That is, an asymptote is a line to which a function approaches indefinitely, without ever touching it.

Being a rational function that which can be expressed as the quotient of two polynomials, a vertical asymptote occurs when the denominator is 0, that is, where the function is not defined. In this case:

x - q= 0

Solving:

x= q

Being the line x=4 the vertical asymptote, then

<u><em>4=q</em></u>

Then the function f (x) is:

f(x)=y=\frac{p+8}{x-4}

The y intercept is (0,4). This is, x= 0 and y=4. Replacing:

4=\frac{p+8}{0-4}

Solving:

4=\frac{p+8}{-4}

4*(-4)= p+8

-16= p+8

-16 - 8= p

<u><em>-24= p</em></u>

<u><em>The value of q and p is 4 and -24  respectively.</em></u>

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3 years ago
What is the probability that a marble chosen at random is shaded or is labeled with a multiple of 3?
kiruha [24]

Answer:

six/eleventh

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3 years ago
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