X(2x²-9x+10)=x(2x-5)(x-2)=0.
x=0 is one solution.
2x-5=0 and x-2=0 give us the solutions x=5/2 and x=2.
So x=0, 2 or 5/2.
area of OAB = 72 = (1/2) sin (AOB) * OA * OB solve the above for sin(AOB) to find sin(AOB) = 1/2 area of ODC = 288 = (1/2) sin (DOC) * OD * OD Note that sin(DOC) = sin(AOB) = 1/2, OD = 18 + y and OC = 16 + x and substitute in the above to obtain the first equation in x and y 1152 = (18 + y)(16 + x)...
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Its not in order its 2.34,9/4,2 3/4
The length of the midsegment of an isosceles trapezoid is the sum of the two bases, divided by 2. So this means -
(base 1+base2) / 2
(12+20) / 2
32/2
Length of midsegment = 16
Answer:
Step-by-step explanation:
( 0, 0) and (-3 , -2)
Slope = Change in y ÷ change in x
![= \frac{-2-0}{-3-0}\\\\=\frac{-2}{-3}\\\\=\frac{2}{3}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B-2-0%7D%7B-3-0%7D%5C%5C%5C%5C%3D%5Cfrac%7B-2%7D%7B-3%7D%5C%5C%5C%5C%3D%5Cfrac%7B2%7D%7B3%7D)