Remmber pemdas or gemdas or bodmas or whatever
exponential laws
(x^m)^n=x^(mn)
ok so
(3^2)(2a)^(3/2))^2=
(3^2)(2a)^((3/2)*2)=
(3^2)(2a))^(6/2)=
(3^2)(2a)^3=
(3^2)(8a^3)^3=
(9)(8a^3)=
72a^3
2nd one from left
The question did not show the original vertices of A, B, and C.
Generally, for a triangle ABC that is dilated by a scale factor of four to form triangle A'B'C', the coordinates of vertices A', B', C' are:
For A(x, y)
The coordinate of vertex A' will be A' (4x, 4y)
For B(x, y)
The coordinate of vertex B' will be B' (4x, 4y)
For C(x, y)
The coordinate of vertec C' will be C' (4x, 4y)
Hey there!
The answer to your question is ± 12
To solve the equation x²/-10 = 2, first multiply 10 to both sides:
x² = 20
Then, take the square root from both sides:
x = ± 20
Answer:
ill answer shortly just leaving it here os i dont forget about it
Step-by-step explanation:
Step-by-step explanation:
= 5 • ( 4• x )
= 5 ( 4x )
= 20x
