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Natalija [7]
3 years ago
14

Help me with this question please?

Mathematics
1 answer:
UNO [17]3 years ago
6 0
\bf 3^{n+2}-3^n=8\cdot 3^n\implies \boxed{3^n\cdot 3^2}-3^n=8\cdot 3^n
\\\\\\
\stackrel{common~factor}{3^n}(3^2-1)=8\cdot 3^n\implies 3^2-1=\cfrac{8\cdot \underline{3^n}}{\underline{3^n}}\implies 3^2-1=8
\\\\\\
9-1=8\implies 8=8
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the coordinates of a pentagon ABCDE are A(-5,4),B (1,4),C(1,-1), D(-2,-5) and E(-5,-1) what is the perimeter of the pentagon
kogti [31]
Perimeter is a continuous line forming the boundary of a closed geometrical figure. perimeter of a pentagon = AB+BC+CD+DE+EA (that is 5 sided figure) 
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7 0
3 years ago
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For altitudes up to 36,000 feet, the relationship between ground temperature and atmospheric
Verizon [17]

Answer:

The equation for a is a=-\frac{2000}{7}*(t-g)

The altitute is 101,428.57 feet

Step-by-step explanation:

You know that the relationship between ground temperature and atmospheric  temperature can be described by the formula

t = -0.0035a +g

where:

  • t is the atmospheric  temperature in degrees Fahrenheit
  • a is the altitude, in feet, at which the atmospheric temperature is  measured
  • g is the ground temperature in degrees Fahrenheit.

Solving the equation for a:

-0.0035a +g=t

-0.0035a= t - g

a=\frac{t-g}{-0.0035}

a=-\frac{2000}{7}*(t-g)

<u><em>The equation for a is </em></u>a=-\frac{2000}{7}*(t-g)<u><em></em></u>

If the atmospheric temperature is -305 °F and the ground temperature is 50 °F, then t= -305 °F and g= 50 °F

Replacing in the equation for a you get:

a=-\frac{2000}{7}*(-305-50)

a=-\frac{2000}{7}*(-355)

a= 101,428.57

<u><em>The altitute is 101,428.57 feet</em></u>

4 0
3 years ago
Please help!
mr Goodwill [35]

Answer:

1. \sqrt{74} ft    2. 50\sqrt{2} yards     3. 5\sqrt{35} units.

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Pythagorean's Theorem a^2 + b^2 = c^2

A and b are both side lengths, c is the hypotenuse.

7^2 + 5^2 = 74

sqrt(74) is the answer for 1.

30^2 - 5^2 = 875

Simplify the radical. sqrt(875) --> 5sqrt(35). The answer for three.

There's a rule in geometry that says a diagonal of a square is the same length as taking a side length times the square root of two. There's your answer for two.

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The highest common factor is seven

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