Jake studied x hours for a big test. Julie studied half as long. Write an algebraic expression for long julie studied.

(adapted from Ross, 2.31) Three countries (the Land of Fire, the Land of Wind, and the Land of Earth) each make a 3 person team.

DaniilM [7]

Answer:

The answer is " $\frac{2}{9} \ and \ \frac{1}{9}$ "

Step-by-step explanation:

In point a:

The requires 1 genin, 1 chunin , and 1 jonin to shape a complete team but we all recognize that each nation's team is comprised of 1 genin, 1 chunin, and 1 jonin.

They can now pick 1 genin from a certain matter of national with the value:

$\frac{1}{\binom{3}{1}}=\frac{1}{3} .$

They can pick 1 Chunin form of the matter of national with the value:

$\frac{1}{\binom{3}{1}}=\frac{1}{3} .$

They have the option to pick 1 join from of the country team with such a probability: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$

And we can make the country teams: $3! = 6$ different forms. Its chances of choosing a team full in the process described also are:

$6 \times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{2}{9}.$

In point b:

In this scenario, one of the 3 professional sides can either choose 3 genins or 3 chunines or 3 joniners. So, that we can form three groups that contain the same ninjas (either 3 genin or 3 chunin or 3 jonin).

Its likelihood that even a specific nation team ninja would be chosen is now: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$

Its odds of choosing the same rank ninja in such a different country team are: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$

The likelihood of choosing the same level Ninja from the residual matter of national is: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$ Therefore, all 3 selected ninjas are likely the same grade: $3\times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{1}{9}$

4 0

3 years ago

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The director of a marching band asks the band members to line up in rows of four, but one is left over. Then she tries to line t

Hatshy [7]

There are 81 band members. :-)

4 rows of 20 = 80 ... with one left over = 80 + 1 (81)
6 rows of 13 = 78 ... with three left over = 78 + 3 (81)
7 rows of 11 = 77 ... with four left over = 77 + 4 (81)

5 0

4 years ago

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HELPPP!!!Kelsey uses the similarity statement to describe the triangles below.

Ganezh [65]

RT = 8 , RS = 3 AND ST = 5.4

RV = 4 , RU = 1.5 AND UV = 2.7

∴ RT/RV = 8/4 = 2

AND RS/RU = 3/1.5 = 2

AND ST/UV = 5.4/2.7 = 2

∴Δ RTS IS SIMILAR TO ΔRVU

SO, the best statement is: