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3 years ago

HELPPP!!!Kelsey uses the similarity statement to describe the triangles below.

Mathematics

2 answers:

Ganezh [65]3 years ago

8 0

RT = 8 , RS = 3 AND ST = 5.4

RV = 4 , RU = 1.5 AND UV = 2.7

∴ RT/RV = 8/4 = 2

AND RS/RU = 3/1.5 = 2

AND ST/UV = 5.4/2.7 = 2

∴Δ RTS IS SIMILAR TO ΔRVU

SO, the best statement is:

Each pair of sides corresponds with a common ratio of 2.

Ivahew [28]3 years ago

4 0

Answer:

Step-by-step explanation:

Given is a picture of two triangles formed by two intersecting lines SU and TV intersecting at point R.

Given that RV = 4 cm, RT = 8 cm

VU = 2.7 cm and ST = 5.4 cm

UR = 1.5 cm and RS = 3 cm.

Since these sides are proportional with ratio 2, we can write corresponding sides in order to have similarity

Writing corresponding sidewise we get

VUR is similar to TSR

Or RST is similar to RUV

Thus starts with the same vertex R

RST is clockwise while RUV is anticlockwise.

Hence the following statements are true

ccurate. Each pair of sides corresponds with a common ratio of 2.

Accurate. The description of each triangle begins at the same vertex.

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Read 2 more answers

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Serga [27]

1) If a die is rolled once, determine the probability of rolling a 4: Rolling a 4 is an event with 1 favorable outcome (a roll of 4) and the total number of possible outcomes is 6 (a roll of 1, 2, 3, 4, 5, or 6). Thus, the probability of rolling a 4 is $\frac{1}{6}$ .

If a die is rolled once, determine the probability of rolling at least a 4: Rolling at least 4 is an event with 3 favorable outcomes (a roll of 4, 5, or 6) and the total number of possible outcomes is again 6. Thus, the probability of rolling at least a 4 is $\frac{3}{6}$ = $\frac{1}{2}$ .

<h3>Here are two more examples: </h3>

If a coin is flipped twice, determine the probability that it will land heads both times:

Favorable outcomes: 1 -- HH

Possible outcomes: 4 -- HH, HT, TH, TT

Thus, the probability that the coin will land heads both times is $\frac{1}{4}$ .

If Dan grabs one sock from a drawer containing 3 white socks, 4 blue socks, and 5 yellow socks, what is the probability that he will grab a white sock?

Favorable outcomes: 3 (3 white socks)

Possible outcomes: 12 (3 white socks + 4 blue socks + 5 yellow socks)

Thus, the probability that Dan will grab a white sock is $\frac{3}{12}$ = $\frac{1}{4}$ .