I wonder if you mean to write ![\sqrt[3]{256}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B256%7D)
in place of 
...
If you meant what you wrote, then we have
If you meant to write (the cube root of 256), then we could go on to have
![\sqrt[3]{256}=\sqrt[3]{16^2}=\sqrt[3]{(4^2)^2}=\sqrt[3]{4^4}=\sqrt[3]{4^3\cdot4}=4\sqrt[3]4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B256%7D%3D%5Csqrt%5B3%5D%7B16%5E2%7D%3D%5Csqrt%5B3%5D%7B%284%5E2%29%5E2%7D%3D%5Csqrt%5B3%5D%7B4%5E4%7D%3D%5Csqrt%5B3%5D%7B4%5E3%5Ccdot4%7D%3D4%5Csqrt%5B3%5D4)
Answer:B
Step-by-step explanation:
The experimental probability of the coin landing heads up is 110/200 = 11/20.
The theoretical probability is 1/2
Answer:
2x - 12
Step-by-step explanation:
Given:
-3(6x+4)+20x
Distribute:
-18x-12+20x
Combine like terms:
2x-12
Hope this helps, have a nice day :))
Answer:
1014cm^2
Step-by-step explanation:
find the area of one side and times it by 6 (bc a cube has 6 sides)
13×13=169
169×6=1014
