By using distance formula (which is attached below), you can solve this problem:
√(x2-x1)^2+(y2-y1)^2
(5, -1) and (5, 3)
√(5-5)^2+(3-(-1))^2
√0^2+4^2
√0+16
√16
4
The distance between the two points is 4.
71/20 is not in simplest form because you need to change it into a mixed number by dividing 71 and 20 and putting the remainder over 20.
2+2=4
6+6+6+6=24
66+66666=66732
4+24+66732=66760
D because d is always right hahahahaha