Hope this is a help for u
3x
30
Answer:
Step-by-step explanation:
Given that:
X(t) = be the number of customers that have arrived up to time t.
... = the successive arrival times of the customers.
(a)
Then; we can Determine the conditional mean E[W1|X(t)=2] as follows;
![E(W_!|X(t)=2) = \int\limits^t_0 {X} ( \dfrac{d}{dx}P(X(s) \geq 1 |X(t) =2))](https://tex.z-dn.net/?f=E%28W_%21%7CX%28t%29%3D2%29%20%3D%20%5Cint%5Climits%5Et_0%20%7BX%7D%20%28%20%5Cdfrac%7Bd%7D%7Bdx%7DP%28X%28s%29%20%5Cgeq%201%20%7CX%28t%29%20%3D2%29%29)
![= 1- P (X(s) \leq 0|X(t) = 2) \\ \\ = 1 - \dfrac{P(X(s) \leq 0 , X(t) =2) }{P(X(t) =2)}](https://tex.z-dn.net/?f=%3D%201-%20P%20%28X%28s%29%20%5Cleq%200%7CX%28t%29%20%3D%202%29%20%5C%5C%20%5C%5C%20%3D%201%20-%20%5Cdfrac%7BP%28X%28s%29%20%5Cleq%200%20%2C%20X%28t%29%20%3D2%29%20%7D%7BP%28X%28t%29%20%3D2%29%7D)
![= 1 - \dfrac{P(X(s) \leq 0 , 1 \leq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}](https://tex.z-dn.net/?f=%3D%20%201%20-%20%5Cdfrac%7BP%28X%28s%29%20%5Cleq%200%20%2C%201%20%5Cleq%20X%28t%29%29%20-%20X%28s%29%20%5Cleq%205%20%29%20%7D%7BP%28X%28t%29%20%3D%202%29%7D)
![= 1 - \dfrac{P(X(s) \leq 0 ,P((3 \eq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}](https://tex.z-dn.net/?f=%3D%20%201%20-%20%5Cdfrac%7BP%28X%28s%29%20%5Cleq%200%20%2CP%28%283%20%5Ceq%20X%28t%29%29%20-%20X%28s%29%20%5Cleq%205%20%29%20%7D%7BP%28X%28t%29%20%3D%202%29%7D)
Now ![P(X(s) \leq 0) = P(X(s) = 0)](https://tex.z-dn.net/?f=P%28X%28s%29%20%5Cleq%200%29%20%3D%20P%28X%28s%29%20%3D%200%29)
(b) We can Determine the conditional mean E[W3|X(t)=5] as follows;
![E(W_1|X(t) =2 ) = \int\limits^t_0 X (\dfrac{d}{dx}P(X(s) \geq 3 |X(t) =5 )) \\ \\ = 1- P (X(s) \leq 2 | X (t) = 5 ) \\ \\ = 1 - \dfrac{P (X(s) \leq 2, X(t) = 5 }{P(X(t) = 5)} \\ \\ = 1 - \dfrac{P (X(s) \LEQ 2, 3 (t) - X(s) \leq 5 )}{P(X(t) = 2)}](https://tex.z-dn.net/?f=E%28W_1%7CX%28t%29%20%3D2%20%29%20%3D%20%5Cint%5Climits%5Et_0%20X%20%28%5Cdfrac%7Bd%7D%7Bdx%7DP%28X%28s%29%20%5Cgeq%203%20%7CX%28t%29%20%3D5%20%29%29%20%5C%5C%20%5C%5C%20%20%3D%201-%20P%20%28X%28s%29%20%5Cleq%202%20%7C%20X%20%28t%29%20%3D%205%20%29%20%20%5C%5C%20%5C%5C%20%3D%201%20-%20%5Cdfrac%7BP%20%28X%28s%29%20%5Cleq%202%2C%20X%28t%29%20%3D%205%20%7D%7BP%28X%28t%29%20%3D%205%29%7D%20%5C%5C%20%5C%5C%20%3D%201%20-%20%5Cdfrac%7BP%20%28X%28s%29%20%5CLEQ%202%2C%203%20%28t%29%20-%20X%28s%29%20%5Cleq%205%20%29%7D%7BP%28X%28t%29%20%3D%202%29%7D)
Now; ![P (X(s) \leq 2 ) = P(X(s) = 0 ) + P(X(s) = 1) + P(X(s) = 2)](https://tex.z-dn.net/?f=P%20%28X%28s%29%20%5Cleq%202%20%29%20%3D%20P%28X%28s%29%20%3D%200%20%29%20%2B%20P%28X%28s%29%20%3D%201%29%20%2B%20P%28X%28s%29%20%3D%202%29)
(c) Determine the conditional probability density function for W2, given that X(t)=5.
So ; the conditional probability density function of
given that X(t)=5 is:
![f_{W_2|X(t)=5}}= (W_2|X(t) = 5) \\ \\ =\dfrac{d}{ds}P(W_2 \leq s | X(t) =5 ) \\ \\ = \dfrac{d}{ds}P(X(s) \geq 2 | X(t) = 5)](https://tex.z-dn.net/?f=f_%7BW_2%7CX%28t%29%3D5%7D%7D%3D%20%28W_2%7CX%28t%29%20%3D%205%29%20%5C%5C%20%5C%5C%20%3D%5Cdfrac%7Bd%7D%7Bds%7DP%28W_2%20%5Cleq%20s%20%7C%20X%28t%29%20%3D5%20%29%20%20%5C%5C%20%5C%5C%20%20%3D%20%5Cdfrac%7Bd%7D%7Bds%7DP%28X%28s%29%20%5Cgeq%202%20%7C%20X%28t%29%20%3D%205%29)
Answer:
- yes
- no
Step-by-step explanation:
When a number of similar calculations are required, a spreadsheet can reduce the tedium.
1. The price is a constant $1.88 per pound, so is proportional to the weight.
_____
2. The price is not proportional to the number of toppings.
__
The cost of the pizza is $8.99 plus $1.50 per topping. The base cost being non-zero ensures that the overall cost is not proportional to the number of toppings.
Answer:
Wait I only see the part where it says “what is the y-intercept and x-intercept of” but I don’t see an equation :/
Step-by-step explanation:
5x²+y²=3
by implicit differentiation we shall have:
10x+2yy'=0
the second derivative will be:
10+2y"=0
2y"=-10
y"=-5