Answer:
6
Step-by-step explanation:
-The different ways of two head and two tails in 4 tosses can be determined by drawing the sample space:

-The sample space of the four tosses is as above. Hence, they are 6 different ways to get 2 heads and 2 tails.
If the box is truly a cube, then all 3 of its dimensions are the same . . . the cube root of 90. There's no "might" about it.
The diagram can be redrawn as,
The value of x and y can be determined as,
![\begin{gathered} \tan C=\frac{AB}{BC} \\ \tan 45^{\circ}=\frac{x}{7\sqrt[]{2}} \\ x=7\sqrt[]{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctan%20C%3D%5Cfrac%7BAB%7D%7BBC%7D%20%5C%5C%20%5Ctan%2045%5E%7B%5Ccirc%7D%3D%5Cfrac%7Bx%7D%7B7%5Csqrt%5B%5D%7B2%7D%7D%20%5C%5C%20x%3D7%5Csqrt%5B%5D%7B2%7D%20%5Cend%7Bgathered%7D)
![\begin{gathered} \cos C=\frac{BC}{AC} \\ \cos 45^{\circ}=\frac{7\sqrt[]{2}}{y} \\ y=14 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ccos%20C%3D%5Cfrac%7BBC%7D%7BAC%7D%20%5C%5C%20%5Ccos%2045%5E%7B%5Ccirc%7D%3D%5Cfrac%7B7%5Csqrt%5B%5D%7B2%7D%7D%7By%7D%20%5C%5C%20y%3D14%20%5Cend%7Bgathered%7D)
Thus, option (D) is the correct solution.