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erik [133]
3 years ago
11

Can anyone help me with ratios

Mathematics
1 answer:
Elden [556K]3 years ago
5 0
Well I am not good with ratios but I could try. What do you need help with?
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I need help with this problem please help :)
wel
Hello! To find the answer to this, let’s do 6x + 4x = 180. Combine like terms and you get that 10x = 180. Divide each side by 10 in order to get 18. Angle 1 = 108 degrees and Angle 12 = 72 degrees. Odd number angles match each other and even number angles match each other. In this case, 5 has the same angle measurement as 1, which is 108. The answer is D: 108 degrees.
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3 years ago
A 176 inch pole is leaning up against a wall, but is sliding down the wall so that the vertical distance between the top of the
natta225 [31]

Answer:

... Wall, But Is Sliding Down The Wall So That The Vertical Distance Between The Top Of The Pole And The Floor Is Decreasing At A Rate Of 4 Inches Per Second. How Fast Is The Horizontal Distance Between The Bottom Of The Pole And ... A 176 inch pole is leaning up against a wall, but is sliding down the wall so that the ...

Step-by-step explanation:

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3 years ago
Help please!!! I need it!
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Answer:

1300.62

Step-by-step explanation:

thank me later lolol.

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3 years ago
Explain how you simplfy 5(4i - 3m) + 2m
Galina-37 [17]

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5 0
3 years ago
Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation
just olya [345]

Answer:

The particle will travel 6 feet in first 2 seconds.

Step-by-step explanation:

We have been given that a particle moves according to the velocity equation v(t)= 6t^2-18t+12. We are asked to find the distance that the particle will travel in its first 2 seconds.

s(t)=\int |v(t)|dt

s(t)=\int\limits^2_0 |6t^2-18t+12|dt

Now, we will eliminate the absolute value sign as:

s(t)=\int\limits^1_0 6t^2-18t+12dt+\int\limits^2_1 -6t^2+18t-12dt

s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1

s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1

s(2)=2(1)^3-9(1)^2+12(1)-(2(0)^3-9(0)^2+12(0))-2(2)^3+9(2)^2-12(2)-(-2(1)^3+9(1)^2-12(1))

s(2)=2-9+12-(0)-16+36-24-(-2+9-12)

s(2)=5-(0)-4-(-5)

s(2)=5-4+5

s(2)=6

Therefore, the particle will travel 6 feet in first 2 seconds.

   

 

7 0
3 years ago
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