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nydimaria [60]
3 years ago
6

Which inequality can be used to find the possible number of nickels, n, in her coin collection.

Mathematics
1 answer:
amid [387]3 years ago
4 0
A. n+8<20 because she is gaining !


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Simplify the expression -3z(1.8z-2.2).
alexdok [17]

Answer:

- 5.4z {}^{2}  + 6.6z

Step-by-step explanation:

Given:

-3z(1.8z-2.2)

Solution:

Applying Distributive property,we obtain

  • (−3z)(1.8z)+(−3z)(−2.2)

Simplifying using PEMDAS:

  • - 5.4z {}^{2}  + 6.6z

Done!

5 0
2 years ago
(-8,3)(-3,-4.5) what is zero of g?​
Crank

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the daimeter of the heart of the heart of the heart

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3 years ago
Find the integral of sqrt(4x-x^2)dx.
lukranit [14]
∫ √(4x - x²) dx
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6 0
3 years ago
A rectangle is to be inscribed in an isosceles right triangle in such a way that one vertex of the rectangle is the intersection
svet-max [94.6K]

Answer:

x  =  2  cm

y  = 2  cm

A(max) =  4 cm²

Step-by-step explanation: See Annex

The right isosceles triangle has two 45° angles and the right angle.

tan 45°  =  1  =  x / 4 - y        or     x  =  4  -  y     y  =  4  -  x

A(r)  =  x* y

Area of the rectangle as a function of x

A(x)  =  x  *  (  4  -  x )       A(x)  =  4*x  -  x²

Tacking derivatives on both sides of the equation:

A´(x)  =  4 - 2*x             A´(x)  =  0            4   -  2*x  =  0

2*x  =  4

x  =  2  cm

And  y  =  4  - 2  =  2  cm

The rectangle of maximum area result to be a square of side 2 cm

A(max)  = 2*2  =  4 cm²

To find out if A(x) has a maximum in the point  x  =  2

We get the second derivative

A´´(x)  =  -2           A´´(x)  <  0   then A(x) has a maximum at  x = 2

5 0
3 years ago
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