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4 years ago

12

Change the improper fraction to a mixed number 62/13 will get 27points

1 answer:

s344n2d4d5 [400]4 years ago

6 0

The answer is 4 10/13.

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Find dy dx of y equals the secant of the square root of x.

iVinArrow [24]

$\bf y=sec(\sqrt{x})\implies y=sec\left( x^{\frac{1}{2}} \right)\implies \cfrac{dy}{dx}=\stackrel{\textit{chain rule}}{sec\left( x^{\frac{1}{2}} \right)tan\left( x^{\frac{1}{2}} \right)\cdot \cfrac{1}{2}x^{-\frac{1}{2}}} \\\\\\ \cfrac{dy}{dx}=sec\left( x^{\frac{1}{2}} \right)tan\left( x^{\frac{1}{2}} \right)\cdot \cfrac{1}{2x^{\frac{1}{2}}}\implies \cfrac{dy}{dx}=\cfrac{sec\left( \sqrt{x} \right)tan\left( \sqrt{x} \right)}{2\sqrt{x}}$

5 0

3 years ago

Please help! Will give brainliest!:)

Mrrafil [7]

Answer:

Ex1: If $1000 is invested now with simple interest of 8% per year. Find the new amount after two years. P = $1000, t = 2 years, r = 0.08.

Step-by-step explanation:

hope this helps

8 0

3 years ago

what is an equation of the line that is perpendicular to line y= -1/2x -2 and passes through the point (0,-4)?

LiRa [457]

Answer:

$y = 2x -4$

Step-by-step explanation:

$y = -\frac{1}{2}x - 2\ \ \ \ \ \ (0, -4)$

To find the perpendicular equation of a line,

You need the product of their gradients to be -1

$-\frac{1}{2} \times ? = -1$

Divide both sides by $-\frac{1}{2}$

? = 2

The gradient of the perpendicular line is 2

Straight line formula is in the form $y = mx + c$

$y = 2x + c$

We're nearly there, we just need to find out c.

Luckily, we're given a point $(0, -4)$

$(x, y) = (0, -4)$

$y = 2x + c$

$-4 = 2(0) + c\\-4 = 0 + c\\c = -4$

We then end up with...

$y = 2x -4$

3 0

2 years ago

Answer question 3 I need help plz

dusya [7]

Hey to get your answers with out asking someone get Mathaway it will tell u all the answers you want really easy to use ☺☺

6 0

3 years ago

You baked 42 chocolate cupcakes and 28 red velvet cupcakes. You package them in boxes that have the same ratio of chocolate to r

dybincka [34]

42:28
36:24
24:16

16 red velvet cupcakes with 24 chocolate

6 0

4 years ago