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BaLLatris [955]
2 years ago
10

The high temperature on Friday was 8 degrees above zero. The low temperature was 3 degrees below zero. Which expression gives th

e average of the low and high temperatures?
Please hurry I am timed

Mathematics
1 answer:
alexandr1967 [171]2 years ago
8 0

Answer:

Option 2, (-3+8)/2

Step-by-step explanation:

Average: Sum of two numbers/ How many numbers

Sum: -3+8

Amount of Numbers: 2

(-3+8)/2

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Is 0.3/0.9 rational?
mario62 [17]

Answer:

Rational

Step-by-step explanation:

Repeating decimals can be represented as a ratio of two integers.

5 0
3 years ago
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100 points for the CORRECT ANSWER
OLga [1]

Answer: D

Step-by-step explanation:

It is a linear function and the slope is negative and the y intercept is negative.

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For the complex number 10+12i identify the real part and the imaginary part
SpyIntel [72]
Complex number = a +bi

a is a real part, bi - an imaginary part

So, in <span>10+12i 
10 is a real part, 12i is an imaginary part.</span>
7 0
3 years ago
Need help and explain it plz
FinnZ [79.3K]
Ok so you could use the equation h=t divided by w.
h represents the hours volunteered in one week.
t represents the amount of hours volunteered in the original amount of weeks.
w represents the original amount of weeks.
When you plug In the numbers you get h=72 divided by 12 which gives you h=6 so Penn volunteered 6 hours in one week.
You know the answer is reasonable because there are 168 hours in a week, so Penn could easily spend 6 hours a week volunteering.
Sorry if my explanation is confusing, but I tried to help. Good luck :)
8 0
3 years ago
Help pls help pls help
fiasKO [112]

Answer:

1/4 of a mile in 1/10 of an hour

you can set up a proportion

(1/4)/(1/10)=2/H

you can now simplify or cross multiply

simplifying the left side

(1/4) divided by (1/10) equals (1/4) times (10/1)

(1/4)*(10/1)=10/4=5/2

5/2=2/H

cross multiply

5H=2*2

5H=4

H=4/5 of an hour or (4/5)*60=48 minutes

another solution...

2/(1/4)=8 and 8*(1/10)=8/10=4/5 of an hour or 48 minutes again

4 0
1 year ago
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