The height of broken part of tree from ground is 5.569m.
Justification:
Let BD is a tree of height 12 m.
<u>Suppose it got bent at a point C and let the part CD take the position CA, meeting the ground at A</u>.
i.e., CD = AC = h m
<u>Broken part makes 60° angle from ground</u>
So, ∠BAC = 60°
<u>Now, height of remaining part of tree</u> = (12 – h)m.
In right angled ∆ABC,
sin 60° = BC/AC
⇒ √3/2 = (12 - h)/h
⇒ √3h = 2(12 – h)
⇒ √3h = 24 – 2h
⇒ √3h + 2h = 24
⇒ h(√3 + 2) = 24
⇒ h(1.732 + 2) = 24
⇒ h(3.732) = 24
⇒ h = 24/3.732 = 6.4308 m
<u>Hence, height of broken tree from ground</u>
⇒ BC = 12 – h
⇒ 12 – 6.4308 = 5.569m
<u>Hence, tree is broken 5.569 m from ground</u>.
<u>Note</u>: See attached picture.
Answer:The area of the base will be (1)(3) m
The area of the right and left lateral faces will be (1)(2) = 2m
The area of the front and back lateral faces will be (2)(3) = 6m
The lateral area of the prism will be 16 m
Step-by-step explanation:
Answer:
7.583333 / 7 7/12
Step-by-step explanation:
2 1/3 × 3 1/4
2 1/3=7/3
3 1/4= 13/4
7/3 * 13/4
=91/12
=7 7/12
Answer:
Step-by-step explanation:
We have been given the equation
and we are asked to apply the square root property of equality to our given a equation and isolate the variable
First, take the square root of both sides of our equation
<em>THEREFORE, THERE ARE TWO SOLUTIONS FOR OUR GIVEN EQUATION</em>
<em>
</em>
<u><em>PLEASE</em><em> </em><em>MAKR</em><em> </em><em>ME</em><em> </em><em>BRAINLIEST</em><em> </em><em>IF</em><em> </em><em>YOU</em><em> </em><em>ARE</em><em> </em><em>HAPPY</em><em> </em><em>WITH</em><em> </em><em>THE</em><em> </em><em>ANSWER</em></u>
Draw a right triangle to represent the problem.
The vertical height of the triangle is 9 ft, and it represents the tree.
The horizontal length, at the bottom of the tree is ground level and has a length of 13 ft.
Let x = angle of elevation.
By definition,
tan x = 9/13 = 0.6923
x = arctan(0.6923) = 34.7 deg. = 35 deg (approx)
Answer: 35°
