Ask question

Ask question

All categories

vampirchik [111]

3 years ago

9

If a dozen chicken eggs costs $1.50 how much would 4 eggs cost?

2 answers:

mash [69]3 years ago

8 0

Answer:

$0.50

Step-by-step explanation:

1.50/12= 0.125

0.125 times 4 = .50

Ivenika [448]3 years ago

4 0

1.50 / 4 = .50 , $.50 for 4 eggs

You might be interested in

In triangle ABC the measure of A is 33° and the measure of C is 90° . what is the measure of B

Masteriza [31]

Answer:

57°

Step-by-step explanation:

ALL angles in a triangle add up to 180°

SO, if we know the sum of two angles which is 123° (why: 33+90=123), all we have to do is subtract this number from 180 to get the measure of the 3rd angle. Which in this case is 57°

6 0

2 years ago

How do you you divide 67by6

Law Incorporation [45]

You first set it up as long division.
Second you would find out how many times 6 goes into 67, so count by 6's until you get close 67.
Third once you get that number you write it on top of the long division and then you would subtract whatever that number is below which is 66 because 6 * 11= 66.
So then you would subtract 67 minus 66 which would be 1. Then go from there and you'll get your answer.

Hope this helps!

6 0

3 years ago

Please help me, I’m struggling

Rzqust [24]

Answer:

28 $\sqrt{6}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

$\sqrt{96}$

= $\sqrt{16(6)}$

= $\sqrt{16}$ × $\sqrt{6}$

= 4 $\sqrt{6}$

Then

7 $\sqrt{96}$

= 7 × 4 $\sqrt{6}$

= 28 $\sqrt{6}$

8 0

2 years ago

Bags of pretzels are sampled to ensure proper weight. The overall average for the samples is 9 ounces. Each sample contains 25 b

77julia77 [94]

Answer:

The value is $UCL = 10.8$

Step-by-step explanation:

From the question we are told that

The sample mean is $\= x = 9 \ ounce$

The sample size is n = 25

The standard deviation is $\sigma = 3 \ ounce$

Given that the sample size is not large enough i.e n< 30 we will make use of the student t distribution table

From the question we are told the confidence level is 99.7% , hence the level of significance is

$\alpha = (100 -99.7 ) \%$

=> $\alpha = 0.003$

Generally the degree of freedom is $df = n- 1$

=> $df = 25 - 1$

=> $df = 24$

Generally from the student t distribution table the critical value of $\frac{\alpha }{2}$ at a degree of freedom of $df = 24$ is

$t_{\frac{\alpha }{2} , 24 } = 3.0$

Generally the margin of error is mathematically represented as

$E = t_{\frac{\alpha }{2} , 24} * \frac{\sigma }{\sqrt{n} }$

=> $E = 3.0 * \frac{3 }{\sqrt{25} }$

=> $E =1.8$

Gnerally the upper control chart limit for 99.7% confidence is mathematically represented as

$UCL = \= x + E$

=> $UCL = 9 + 1.8$

=> $UCL = 10.8$

4 0

2 years ago

2thousands pluse 14hundreds

snow_tiger [21]

2.000 pluse 4.00=600.000
4 pluse 2=6
thousand pluse hundreds=hundre thousandths

3 0

3 years ago

Read 2 more answers